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Eva8 [605]
3 years ago
13

The original commercial version of Ethernet supported 10 Mbps bandwidth; the version introduced in the early 1990s supports 100

Mbps; and in 1998, Gigabit Ethernet was introduced. All versions use the same data frame formats, with the same maximum PDU sizes, so they can interoperate freely. Given this information and what you know of layered technologies, which of the following statements is true? (Choose all that apply.)
a. Ethernet works at the Data Link and Physical layers of the OSI model, and upgrades to newer, faster versions of Ethernet can be made by changing only the components that work at these layers.b. Ethernet spans several layers and requires a new protocol stack to upgrade to new versions.c. Changes in technology at one layer of the OSI model don’t usually affect the operation of other layers.d. Ethernet isn’t considered a scalable technology.
Computers and Technology
1 answer:
Elodia [21]3 years ago
3 0

Answer: a) and c).

Explanation:

  • Ethernet is a Layer 2 and also Layer 1 Technology (this layer defines the technical details of cabling and connectors), so any upgrade to a newer, faster version (like 100G Ethernet) will be possible changing only the components operating at these layers, without changing anything in the higher layers like IP and TCP, for instance.
  • This is a direct consequence of the OSI layer model foundations, that say basically that each each layer is independent from the others, so the piece of software pertaining to one layer, only interacts with his layer peer in the destination machine.
  • So, any changes to the technology used in one of the layers, don't usually affect the operation of the other layers.
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zmey [24]

Answer:

1. More access to data

2.convenience

3. Easy creation of BI solutions

4. Report creation

5. Saves time

Explanation:

A data warehouse can be described to be an electronic storage system that contains large amount of facts and information which sources for and also maintains data from different sources; either external or internal.

The most important reason for a data warehouse is for it to store great amounts of data to be used for query and also to be used for analysis.

Why do we use a data warehouse?

1. Users have more access to data due to the integration of various sources of data. It makes use of real time data facts

2. You can conveniently store and also create metadata

3. Business intelligence solutions can easily be created using data warehouses.

4. Users can easily create their own reports

5. Data warehouses makes accessing different data sets faster. It is a time saver as business users are not going to spend time trying to retrieve data from various sources.

4 0
3 years ago
A Windows computer is experiencing a problem accessing the Internet. The network patch cable and network interface card have bee
Svet_ta [14]

Answer:

The next step to consider is updating the system's network settings

Explanation:

The next step after testing and verifying that the network patch cable and network interface card are working is to update the network settings to recent configurations.

Updating the system's network include settings of network adapter, LAN / Wi-Fi and TCP/IP.

Looking into your network settings is one of steps of effectively troubleshooting a system's network.

Few settings you could update are

1. LAN settings

2. TCP/IP network protocol properties

3. Network adapter settings

4. Internet connection

Effectively, updating the network settings is the next step. Few things to take note of when updating the network settings are

1. Create Standard Configurations for Device Classifications

2. Maintain the Current and Previous Network Configurations

3. Keep Track of Changes

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8 0
4 years ago
Which of the following is the result of a query?
IgorLugansk [536]
I think the answer is A
6 0
3 years ago
Write a program to add two number marie simulator.
Gnoma [55]
Int a, b;
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8 0
3 years ago
System uses a 6-bit 2’s complement signed integer representation. What is the range of decimal values it can represent?
kap26 [50]

Answer:

-32 to +31

Explanation:

6 bit 2s complement representation will be of the form b1b2b3b4b5b6 where each bit is either 0 or 1.

The largest positive number that can be represented using this scheme is 011111

Translating this to decimal this is 1*2^4 + 1^2^3 + 1^2^2 + 1^2^1 + 1^2^0

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The smallest negative number that can be represented using this scheme is 100000

Translating this to decimal = -1 * 2^5 = -32

So the range of decimal values that can be represented is -32 to +31.

6 0
3 years ago
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