Answer:
Barry had the following:
8 bananas
12 apples
20 kiwi
32 peaches
8 grapefruit
4 mangos
88 total
Step-by-step explanation:
Each of the amounts of fruit can be written in terms of one variable. Starting with bananas as 'x', we can then make different values of 'x' to produce all the other numbers of fruits:
bananas = x
apples = 2x (twice as many bananas)
kiwi = 2.5x (5/6 of applies and bananas combined = 5/6(3x) or 2.5x)
peaches = 3.5x + 4 (sum of bananas and kiwis plus four = x + 2.5x + 4)
grapefruit = x (half as many apples = 2x/2)
mango = 0.5x (20% of kiwi = (0.2)(2.5)x)
88 = x + 2x + 2.5x + 3.5x + 4 + x + 0.5x
88 = 10.5x
8 = x (bananas)
apples = 2x or 16; kiwi = 2.5x or 20, peaches = 3.5x + 4 = 32, grapefruit = x or 8, mangos = 0.5x or 4
7/9==0,7=7/10=70%
2/3==0,6=6/10=60%
More of their homework problems has finished Myron
Answer:
8 units like the top person says
Answer:
$0 < p ≤ $25
Step-by-step explanation:
We know that coach Rivas can spend up to $750 on 30 swimsuits.
This means that the maximum cost that the coach can afford to pay is $750, then if the cost for the 30 swimsuits is C, we have the inequality:
C ≤ $750
Now, if each swimsuit costs p, then 30 of them costs 30 times p, then the cost of the swimsuits is:
C = 30*p
Then we have the inequality:
30*p ≤ $750.
To find the possible values of p, we just need to isolate p in one side of the inequality.
So we can divide both sides by 30 to get:
(30*p)/30 ≤ $750/30
p ≤ $25
And we also should add the restriction:
$0 < p ≤ $25
Because a swimsuit can not cost 0 dollars or less than that.
Then the inequality that represents the possible values of p is:
$0 < p ≤ $25
