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2 years ago

There is 46% hard working Elfs in the North Pole. there is 300 elfs in north pole. How many elfs are hard working

Mathematics

2 answers:

uranmaximum [27]2 years ago

8 0

Answer:

There is 138 Hard working Elves at the North Pole.

Step-by-step explanation:

300× 0.46= 138

sveticcg [70]2 years ago

3 0

Answer:

138 hard working elfs

Step-by-step explanation:

the 46% of 300 is 138

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The mean height of women in a country (ages 20-29) is 64 4 inches A random sample of 50 women in this age group is selected What

Simora [160]

Answer:

0.0721 = 7.21% probability that the mean height for the sample is greater than 65 inches.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 64.4 inches, standard deviation of 2.91

This means that $\mu = 64.4, \sigma = 2.91$

Sample of 50 women

This means that $n = 50, s = \frac{2.91}{\sqrt{50}}$

What is the probability that the mean height for the sample is greater than 65 inches?

This is 1 subtracted by the p-value of Z when X = 65. So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{65 - 64.4}{\frac{2.91}{\sqrt{50}}}$

$Z = 1.46$

$Z = 1.46$ has a p-value of 0.9279

1 - 0.9279 = 0.0721

0.0721 = 7.21% probability that the mean height for the sample is greater than 65 inches.

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2 years ago

Alexis is making goodie bags for her birthday party. She has made 12 bags already.

Genrish500 [490]

20
Needs 20 characters

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2 years ago

Which sum or difference is modeled by the algebra tiles? A. (x2 4x − 2) (x2 − 2x − 4) = 2x2 2x 2 B. (x2 4x − 2) (x2 2x 4) = 2x2

dimulka [17.4K]

Answer:

Because (-x²+2x+3)+(-x²-2x-1) = -x²+2x+3-x²-2x-1 = -2x²+2

Step-by-step explanation:

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1 year ago

Surface area in terms of pi?

Lunna [17]

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3 years ago

Let the random variable X be the outcome of rolling a 6-sided die. Assuming the die is fair, the probability distribution is as

gayaneshka [121]

The answer would be 1.

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2 years ago

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