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artcher [175]
4 years ago
6

Calcium oxide reacts with water in a combination reaction to produce calcium hydroxide: In a particular experiment, a 2.00 g sam

ple of a CaO is reacted with excess water and 2.14 grams of Ca(OH)2 is recovered. What is the percentage yield of this experiment?
Chemistry
1 answer:
telo118 [61]4 years ago
4 0

Answer:

The answer to your question is:  yield = 81 %

Explanation:

Data

Calcium oxide mass = 2 g

Calcium hydroxide mass = 2.14 g

yield = ?

Process

Reaction

                     CaO   +   H₂O    ⇒     Ca(OH)₂

MW CaO = 40 + 16 = 56 g

MW Ca(OH)₂ = 40 + 32 + 2 = 74 g

                  56 g of CaO -----------------   74 g of Ca(OH)₂

                  2 g                ----------------    x

                 x = (2 x 74)/ 56

                 x = 2.64 g of  Ca(OH)₂

yield = experimental / theoretical x 100

yield = 2.14 / 2.64 x 100

yield = 81 %

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A chemist determines by measurements that 0.0550 moles of nitrogen gas participate in a chemical reaction. Calculate the mass of
shtirl [24]

The mass of nitrogen gas that participated in the chemical reaction is 1.54g

HOW TO CALCULATE MASS OF AN ELEMENT:

  • Mass of a substance can be calculated by multiplying the number of moles in mol of the substance by its molecular mass in g/mol. That is;

  • mass (M) = molar mass (MM) × number of moles (n)

According to this question, a chemist determines by measurements that 0.0550 moles of nitrogen gas (N2) participate in a chemical reaction.

  • The molecular mass of nitrogen gas (N2) = 14.01(2)

= 28.02g/mol

Hence, the mass of the nitrogen gas that participated in the chemical reaction is calculated as follows:

  • Mass (g) = 0.0550 mol × 28.02 g/mol

  • Mass = 1.5411

Therefore, the mass of nitrogen gas that participated in the chemical reaction is 1.54g

Learn more: brainly.com/question/18269198

6 0
3 years ago
What is the reaction type of 3ZnS+ 2AlP = 1Zn3P2 + 1Al2S3 ?
adelina 88 [10]

Answer: double displacement

Explanation:

A double displacement reaction is one in which exchange of ions take place. The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.  

The balanced chemical equation is:

3ZnS+2AlP\rightarrow Zn_3P_2+Al_2S_3

Thus as ions get exchanged , it is double displacement reaction.

4 0
3 years ago
In Chapter 4, we will learn that single bonds experience free rotation at room temperature, while double bonds do not. Consider
il63 [147K]

Answer:

Explanation:

The main objective here is to draw a diagram of an heterocyclic compound containing two C-N bonds in the structure. One with free rotation, as expected for a single bond, but the other C-N bond exhibits restricted rotation. After that ; we will identify the C-N bond with restricted rotation, and also justify our answer by drawing resonance structures.

So; the first image below shows the structure of the heterocyclic compound containing two C-N bonds in the structure with One with free rotation, as expected for a single bond, but the other C-N bond exhibits restricted rotation. From the first diagram. the squared area indicates the  C-N bond that exhibits restricted rotation.

The amide bonds in the C-N bonds offers the resonance characteristics and thus exhibits restricted rotation. The resonance is shown in the second image below

4 0
4 years ago
What are independant variables
Phoenix [80]

Answer:

a variable (often denoted by x ) whose variation does not depend on that of another.

Explanation:

8 0
3 years ago
Given the following information:Br2 bond energy = 193 kJ/mol F2 bond energy = 154 kJ/mol 1/2Br2(g) + 3/2F2(g) -> BrF3(g) = –3
arlik [135]

Answer:

C) 712 KJ/mol

Explanation:

  • ΔH°r = Σ Eb broken - Σ Eb formed
  • 1/2Br2(g) + 3/2F2(g) → BrF3(g)

∴ ΔH°r = - 384 KJ/mol

∴ Br2 Eb = 193 KJ/mol

∴ F2 Eb = 154 KJ/mol

⇒ Σ Eb broken = (1/2)(Br-Br) + (3/2)(F-F)

⇒ Σ Eb broken =  (1/2)(193 KJ/mol) + (3/2)(154 KJ/mol) = 327.5 KJ/mol

∴ Eb formed: Br-F

⇒ Σ Eb formed (Br-F) = Σ Eb broken - ΔH°r

⇒ Eb (Br-F) = 327.5 KJ/mol - ( - 384 KJ/mol )

⇒ Eb Br-F = 327.5 KJ/mol + 384 KJ/mol = 711.5 KJ/mol ≅ 712 KJ/mol

8 0
3 years ago
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