1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Korolek [52]
3 years ago
14

A solution of baking soda and water has a pH of 8.40. What type of solution is this?

Chemistry
1 answer:
Gwar [14]3 years ago
7 0
The solution is basic.
pH scale can be used to find out how acidic or basic a solution is .
When pH = 7 the solution is neutral,
pH < 7 solution is acidic
pH > 7 solution is neutral
Since the pH of solution is 8.40 then value is more than 7 therefore baking Soda and water is basic.
You might be interested in
The atoms, molecules, or compounds present at the start of a chemical reaction that participate in the reaction.
Art [367]
For the first one the answer is B. and the second one is D.
4 0
3 years ago
Read 2 more answers
Gold has a density of 1,200 lb./ft. What is the density of gold in g/em? For conversion factors use I lb. 453.6 g, and l inch-2.
Jlenok [28]

<u>Answer:</u> The density of gold in g/cm^3 is 19.22g/cm^3

<u>Explanation:</u>

Density is defined as the ratio of mass of the object and volume of the object. Mathematically,

\text{Density}=\frac{\text{Mass of the object}}{\text{Volume of the object}}

We are given:

Density of gold = 1200lb/ft^3

Using conversion factors:

1 lb = 453.6 g

1 feet = 12 inches

1 inch = 2.54 cm

Converting given quantity into g/cm^3, we get:

\Rightarrow (\frac{1200lb}{ft^3})\times (\frac{453.6g}{1lb})\times (\frac{1ft}{12inch})^3\times (\frac{1inch}{2.54cm})^3\\\\\Rightarrow 19.22g/cm^3

Hence, the density of gold in g/cm^3 is 19.22g/cm^3

6 0
3 years ago
How many grams of potassium sulfate should be weighed to prepare 100 ppm of potassium in 250mL of solution if the purity of the
KIM [24]

Answer:

R=0.0564g K2SO4

4 0
3 years ago
What can be produced from chemical energy? matter heat sunlight pollution
Ivenika [448]

Answer:

pollution

Explanation:

8 0
2 years ago
How many particles are in 100.0 grams of gold
Tcecarenko [31]
First, we need to convert the grams of gold into mole using the molar mass (molecular weight) of gold, and then into particles using avogadro's number (1 mol= 6.02 x 10^23)

molar mass of gold= 197 grams/ mole

100.0 grams (1 mole/ 197 grams) x (6.02 x 10^23 particles/ 1 mole) = 3.06 x 10^23
3 0
2 years ago
Other questions:
  • What is the total number of atoms in 1.0 mole of
    13·1 answer
  • What do weather maps display?
    7·2 answers
  • Which is true about the pH values of a 1.0 M solution of HCl (a strong acid) and a 1.0 M solution of HC2H3O2 (a weak acid)?
    6·1 answer
  • Which of the following places the elements in the correct order of increasing first ionization energy?
    5·1 answer
  • If your car gets 30.3 mi/gal, how many gallons of gasoline would you use if you drove 506.3 miles? 1 mile = 5280 ft (exactly) In
    8·2 answers
  • 8. How much heat is released when 85.0 g of steam condense to liquid water?
    5·1 answer
  • 17) A 0.20 M solution of HCl with a volume of 15.0 mL is exactly neutralized by the 0.10 M solution of NaOH with what volume? HI
    5·1 answer
  • weeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee
    12·2 answers
  • When hydrogen is fused into helium, energy is released from
    12·1 answer
  • What is the change in the freezing point of water when 35.0 g of sucrose is
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!