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Korolek [52]
3 years ago
14

A solution of baking soda and water has a pH of 8.40. What type of solution is this?

Chemistry
1 answer:
Gwar [14]3 years ago
7 0
The solution is basic.
pH scale can be used to find out how acidic or basic a solution is .
When pH = 7 the solution is neutral,
pH < 7 solution is acidic
pH > 7 solution is neutral
Since the pH of solution is 8.40 then value is more than 7 therefore baking Soda and water is basic.
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Plastic pollution is the correct answer
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Predict, using Boyle’s Law, what will happen to a balloon that an ocean diver takes to a pressure of 202 kPa (normal atmospheric
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Explanation:

Balloon that an ocean diver takes to a pressure of 202 k Pa will get reduced in size that is the volume of the balloon will get reduced. This is because pressure and volume of the gas are inversely related to each other.

According to Boyle's law: The pressure of the gas  is inversely proportional to the volume occupied by the gas at constant temperature(in Kelvins).

pressure\propto \frac{1}{volume} (At constant temperature)

The pressure beneath the sea is 202 kPa and the atmospheric pressure  is 101.3 kPa . This increase in pressure will result in decrease in volume occupied by the gas inside the balloon with decrease in size of a balloon. Hence, the size of the balloon will get reduced at 202 kPa (under sea).

7 0
3 years ago
Given that the molar mass of NaCl is 58.44 g/mol, what is the molarity of a solution that contains 87.75 g of NaCl in 500. mL of
Stells [14]

<u>Given information:</u>

Mass of NaCl (m) = 87.75 g

Volume of solution (V) = 500 ml = 0.5 L

Molar mass of NaCl (M) = 58.44 g/mol

<u>To determine:</u>

The molarity of NaCl solution

<u>Explanation:</u>

Molarity is defined as the number of moles of solute(n) dissolved per liter of solution (V)

i.e. M = moles of solute/liters of solution = n/V

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moles of NaCl = 87.75 g/58.55 g.mol-1 = 1.499 moles

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<u>Ans: (D)</u>

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_Z^A\textrm{X}\rightarrow _{Z+1}^A\textrm{Y}+_{-1}^0\beta

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_{92}^{239}\textrm{U}\rightarrow _{93}^{239}\textrm{Np}+_{-1}^0\beta

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6 0
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