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kupik [55]
3 years ago
15

What is the new boiling point if 25 g of NaCl is dissolved in 1.0 kg of water

Chemistry
1 answer:
Inessa05 [86]3 years ago
8 0
The correct answer for the question that is being presented above is this one: 

Given that:
delta Tb = Kbm Kb H2O = 0.52 degrees C/m 
<span>delta Tf = Kfm Kf H2O = 1.86 degrees C/m 
</span>
We need to know the formula for Molality.
molality = mol solute / kg solvent 

<span>We are given the amount of solute in grams
Since amount of solute is given in moles, we have to convert 25 g NaCl to moles. Divide by molar mass. </span>

<span>25 g NaCl / 58.5 g/mol = 0.427 mol </span>

<span>Then, use the formula for molality. </span>

<span>molality = mol solute / kg solvent </span>
<span>= 0.427 / 1 </span>
<span>= 0.427 m </span>

<span>Use now the formula to get the boiling point.</span>

<span>delta Tb = Kbm </span>
<span>= (0.52)(0.427) </span>
<span>= 0.22C </span>
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