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kupik [55]
3 years ago
15

What is the new boiling point if 25 g of NaCl is dissolved in 1.0 kg of water

Chemistry
1 answer:
Inessa05 [86]3 years ago
8 0
The correct answer for the question that is being presented above is this one: 

Given that:
delta Tb = Kbm Kb H2O = 0.52 degrees C/m 
<span>delta Tf = Kfm Kf H2O = 1.86 degrees C/m 
</span>
We need to know the formula for Molality.
molality = mol solute / kg solvent 

<span>We are given the amount of solute in grams
Since amount of solute is given in moles, we have to convert 25 g NaCl to moles. Divide by molar mass. </span>

<span>25 g NaCl / 58.5 g/mol = 0.427 mol </span>

<span>Then, use the formula for molality. </span>

<span>molality = mol solute / kg solvent </span>
<span>= 0.427 / 1 </span>
<span>= 0.427 m </span>

<span>Use now the formula to get the boiling point.</span>

<span>delta Tb = Kbm </span>
<span>= (0.52)(0.427) </span>
<span>= 0.22C </span>
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natural rubidium has the average mass of 85.4678 and is composed of isotopes 85 Rb(mass = 84.9117) and 87 Rb. The ratio of atoms
mote1985 [20]

Answer:

Mass of Rb-87 is 86.913 amu.

Explanation:

Given data:

Average mass of rubidium = 85.4678 amu

Mass of Rb-85 = 84.9117

Ratio of 85Rb/87Rb in natural rubidium = 2.591

Mass of Rb = ?

Solution:

The ration of both isotope is 2.591 to 1. Which means that for 2.591 atoms of Rb-85 there is one Rb-87.

For 100% naturally occurring Rb = 2.591 + 1 = 3.591

% abundance of Rb-85 = 2.591/ 3.591 = 0.722

% abundance of Rb-87 = 1 - 0.722= 0.278

84.9117 × 0.722 + X × 0.278 = 85.4678

61.306 + X × 0.278 = 85.4678

X × 0.278 = 85.4678 - 61.306

X × 0.278 = 24.1618

X =  24.1618 / 0.278

X = 86.913 amu

8 0
3 years ago
Initial temperature of metal= 100 C°
Vilka [71]

Water is 22.4

Final for both us 27.1

Explanation:

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3 0
3 years ago
Given the mass of the reactants add up to 49 grams, what is the total mass of the products
valina [46]

If the total mass of the reactants is 49g then the mass of the products also equals 49g.

It is due to the law of conservation of mass.

Mass can neither be created nor be destroyed.

5 0
3 years ago
What is the molar mass of calcium chloride dihydrate (CaCl2 • 2H2O)? Be sure to
Verdich [7]

Calcium chloride dehydrate (CaCl₂ · 2 H₂O) have a molar mass equal to 147 g/mol.

Explanation:

To calculate the molar mass of calcium chloride dehydrate (CaCl₂ · 2 H₂O) we use the following formula:

molar mass of CaCl₂ · 2 H₂O = atomic weight of Ca × 1 + atomic weight of Cl × 2 + atomic weight of H × 4 + atomic weight of O × 2

molar mass of CaCl₂ · 2 H₂O = 40 × 1 + 35.5 × 2 + 1 × 4 + 16 × 2

molar mass of CaCl₂ · 2 H₂O = 147 g/mol

Learn more about:

molar mass

brainly.com/question/6112557

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4 0
3 years ago
Explain how atoms are held together in covalent bonds. Give an example of a covalent compound.
asambeis [7]

Answer:

Explanation:

Atoms are held together by covalent bonds when they share electrons between themselves.

Covalent bonds are bonds that are formed between non-metals usually with a low electronegative difference between them. In this bond type, two non-metals donate electrons which are shared between the combining atoms and this makes them both like the corresponding noble gases. The shared electrons is what forms the covalent bonds.

An example of covalent bond is HCl, H₂S, SO₂, CO₂, O₂ etc

5 0
3 years ago
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