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4 years ago

Write a word problem that can be solved by ordering 3 decimals to thousands

Mathematics

2 answers:

Roman55 [17]4 years ago

4 0

189.444 should be right if my calculations are

Elis [28]4 years ago

4 0

Answer:

3 runners run a 100 meter race, the time elapsed until they finish are

runner time

A 10.124

B 10.121

C 10.128

Who is faster?

To answer this question you have to order the three times. Start the comparison with the first one.

A's running time is greater than B's running time but lower than C's running time. Then, A goes in the middle of the ordered list.

Next continue with B. B's running time is the lowest time, so it goes first in the ordered list.

Finally, C's running time is the greatest time, so it goes last in the ordered list. The ordered list is:

runner time

B 10.121

A 10.124

C 10.128

You might be interested in

ok so if you have 3 and 1/4 pizza and want to subtract 3/4 out of it,and get 3x more slices then you had from a friend after sub

Brilliant_brown [7]

Answer:

You have 2 and 1/2 pizzas and your friend has 5/6 of a pizza.

Step-by-step explanation:

You have 3 1/4 pizzas. If you get rid of 3/4 of a pizza, you will end up with 2 2/4 pizzas.

To make it easier, you can just change the values into improper fractions: 3 1/4 = 13/4

13/4 - 3/4 = 10/4

10/4 = 2 2/4 pizzas

(2 2/4 = 2 1/2)

Anyways! You now have 2 and a half pizzas. You have 3 times the amount of pizza that your friend has. In other words, your friend has 1/3 the amount of pizza that you have. You can solve for this in two ways, whichever way you solve it is up to you.

You can solve this problem by dividing the amount of food you have by 3: $\frac{2\frac{1}{2} }{3}$ which equals 0.8333... (the 3 is repeating). But you can just keep your final answer in fraction form if you want to: $\frac{2.5}{3} = \frac{5}{6}$
You can solve this problem by multiplying 1/3 to the amount of food you have: $\frac{1}{3} * 2 \frac{2}{4}\\=\frac{10}{12}\\ =\frac{5}{6}$

You have 2 and 1/2 pizzas and your friend has 5/6 of a pizza.

8 0

3 years ago

Show how you do it please

sergij07 [2.7K]

Answer:

$0.002403$ $= 2.403 * 10^{-3}$

Step-by-step explanation:

Given

$0.002403$

Required

Express as scientific notation

The rule of scientific notation is that:

It is represented in form of: $a * 10^n$ where $1 \le a \le 10$

$0.002403$ will be represented as: a = 2.403; notice that the point was shifted forward by 3 units.

So:

n = -3

The equation becomes:

$a * 10^n$

$0.002403$ $= 2.403 * 10^{-3}$

Approximate

$0.002403$ $= 2.4 * 10^{-3}$

3 0

3 years ago

a bathtub that hols 32 gallons of water contains 12 gallons of water you begin filling it and after 5 minutes the tub is full

kramer

Okay. I am guessing that you are asking for the amount of water poured per minute. The bathtub already holds 12 gallons and 32 - 12 is 20. The tub is full in 5 minutes. Let’s divide. 20/5 is 4. There are 4 gallons of water filled in the tub per minute.

7 0

3 years ago

A group of rowdy teenagers near a wind turbine decide to place a pair of

tamaranim1 [39]

Answer:

a) Sinusoidal functions are y = a sin [b(x-h)] + k (or)

y = a cos [b(x-h)] + k

Where a is amplitude a= (max-min)/2=(16-2)/2=7

period p= 2π/b

b=2π/30

Horizontal transformation to 10 units right h=10

k= (max+min)/2=(16+2)/2=9

h = 7 cos [π/15(t-10)]+ 9

b) t=10min=600 sec

substitue in the above equation

h=5.5m

3 0

3 years ago

Researchers obtained a sample of n = 10 children who attended daycare before starting school. The children are given a standardi

attashe74 [19]

Answer:

$t=\frac{55.5-50}{\frac{4.249}{\sqrt{10}}}=4.093$

$p_v =2*P(t_{9}>4.093)=0.00084$

If we compare the p value and the significance level assumed $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis.

We can say that at 5% of significance the true mean is significantly different from 50.

Step-by-step explanation:

Data given and notation

53, 57, 61, 49, 52, 56, 58, 62, 51, 56

We can calculate the sample mean and deviation with the following formulas:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

$s= \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X))^2}{n-1}}$

And we got:

$\bar X=55.5$ represent the sample mean

$s=4.249$ represent the sample standard deviation

$n=10$ sample size

$\mu_o =50/tex] represent the value that we want to test [tex]\alpha=0.05$ represent the significance level for the hypothesis test (ASSUMED).

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the true mean is equal or not to 50 :

Null hypothesis: $\mu = 50$

Alternative hypothesis: $\mu \neq 50$

Since we don't know the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{55.5-50}{\frac{4.249}{\sqrt{10}}}=4.093$

P-value

We need to calculate the degrees of freedom first given by:

$df=n-1=10-1=9$

Since is a two-sided tailed test the p value would given by:

$p_v =2*P(t_{9}>4.093)=0.00084$

Conclusion

If we compare the p value and the significance level assumed $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis.

We can say that at 5% of significance the true mean is significantly different from 50.

6 0

4 years ago