1) 5t^2 (1 + 6t)
2) 4x^3y^5 (5x + 2y)
3) (5r + 6x)(5r - 6x)
4) (x + 10)(x - 10)
5) (x - 3)^2
6) (x -5)(x - 3)
7) 3(16r^3 + 9)
8) 8(c^3 + 8d^3)
9) (2r - 125)(4r^2 + 250r + 15625)
10) (c + 3)(c - 1)
Answer:
the domain is : D = ]-∞ , -5[ U ]-5 , -3[ U ]-3 , +∞[
Step-by-step explanation:
hello :
f(x) = 9x/(x+5)(x+3)
f exist for : (x+5)(x+3) ≠ 0
(x+5)(x+3)=0
x+5=0 or x+3=0 means : x= - 5 or x= -3
the domain is : D = ]-∞ , -5[ U ]-5 , -3[ U ]-3 , +∞[
1. "the graph has the same zeros" : so let a be the "triple" root of the cubic polynomial function.
2. So f(x)=

3. Don't forget that the expression might have a coefficient b as well, and still maintain the conditions:

4. Now, f(0)=-5 so




5. the function is

where a can be any real number except 0
Answer:
Can you show a picture? Or like tell us the options?
Answer:
I would think it would be C. because there is not other answer.
I hoped this help.
please mark brainliest if correct