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viva [34]
3 years ago
6

You work for a florist. Normally, it’s takes you 20 hours to assemble 10 flower arrangements. How long does it take you to assem

ble one flower arrangement?
Mathematics
2 answers:
Mashcka [7]3 years ago
3 0
2 hours because 20/10 = 2

Vitek1552 [10]3 years ago
3 0
20/10= 2

That is 2 hours per flower arrangement.

So, 

One flower arrangement would take 2 hours to assemble.

I hope this helps!
~kaikers
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Christopher’s hourly salary is $15. If Christopher works 7 hours a day, then how much will be earned in a day?
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7 times 15 = 105. Hope it helps
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Triangle ABC is congruent to triangle DFE. Find x.
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Since side BC must equal FE, x - 13 = 20. Therefore x = 33
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Please help me with this​
Tatiana [17]
<h2><u>Given</u> :</h2>

The given equations are :

\longrightarrow15b + 10g = 8640 \:  \:  \:  \:  \:   - (1)

\longrightarrow b + g = 708 \:  \:  \:  \:  \:  \:  - (2)

Let's solve for g in equation (2) :

\longrightarrow b + g = 708

\longrightarrow g = 708 - b \:  \:  \:  \:  \:  - (3)

now, let's plug value of g from equation (3) into equation (1) :

\longrightarrow15b + 10g = 8640

\longrightarrow15b + 10(708 - b) = 8640

\longrightarrow15b - 10b + 7080 = 8640

\longrightarrow5b = 1560

\longrightarrow b = 312

plugging value of b in equation (3) :

\longrightarrow g = 708 - b

\longrightarrow g = 708 - 312

\longrightarrow g =39 6

since " g " represents ground seats, number of ground seats :

=》396

And " b " represents balcony seat, therefore it is equal to :

=》312

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4 0
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Prove that if one solution for a quadratic equation of theform x2 + bx + c = 0 is rational (where b and c are rational),then the
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Answer:

The other solution of the given equation x² + bx + c = 0   is also rational number.

Step-by-step explanation:

Here, given: ax² + bx + c = 0 is a quadratic equation

Also, one solution  (r)  of equation is RATIONAL.

To show: The other solution (s)  is also RATIONAL

Now, here: as x² + bx + c = 0

Since r and s are the two given solutions, the given equation can be factorized as:

x² + bx + c =  (x -r) (x - s)

Simplifying LHS, we get:

(x -r) (x - s) = x x - r (x) - s (x) +  (r)(s)

                 =  x² + x(-r - s) +  rs

or, x² + bx + c = x² + x(-r - s) +  rs

Comparing the related terms, we get:

b =  (-r - s)    

⇒  b +  s = - r

or, s  = -r - b

Now, given : r = Rational  and the negative of a rational is also rational.

⇒  -r is also rational

Also, difference of two rational number is also rational.

⇒ -r - b is also rational

⇒ s is a RATIONAL NUMBER

Hence, the other solution of the given equation x² + bx + c = 0   is also rational number.

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Step-by-step explanation:

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