Factors of 3x^2y^2+6x^2+12y^2+24
1 answer:
Look for the GCF
GCF = 3
so we have
3 (x^2y^2 + 2x^2 + 4y^2 + 8) Factor by grouping:-
= 3[ x^2(y^2 + 2) + 4(y^2 + 2)]
= 3(x^2 + 4)(y^2 + 2)
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Step-by-step explanation: 0,15 . 16,-12
y1-y2/x1-x2
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