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3 years ago

Factors of 3x^2y^2+6x^2+12y^2+24

1 answer:

4 0

Look for the GCF

GCF = 3

so we have

3 (x^2y^2 + 2x^2 + 4y^2 + 8) Factor by grouping:-

= 3[ x^2(y^2 + 2) + 4(y^2 + 2)]

= 3(x^2 + 4)(y^2 + 2)

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What are the coordinates of the turning point for the function f(x) = (x + 2)3 − 4?

AnnZ [28]

Answer:A

Step-by-step explanation:

Given

$F(x)=(x+2)^3-4$

Turning Point is the point where the graph changes its nature i.e. either increasing to decreasing or decreasing to increasing

to find turning point

$F'(x)=3(x+2)^2+0$

For critical point

F'(x)=0

$3(x+2)^2=0$

x+2=0

x=-2

$F(x)=(-2+2)^3-4=-4$

thus

(-2,-4 ) is the turning Point where Function changes its nature

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