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Lelechka [254]
3 years ago
6

Factors of 3x^2y^2+6x^2+12y^2+24

Mathematics
1 answer:
ddd [48]3 years ago
4 0
Look for  the GCF

GCF = 3

so we have 

3 (x^2y^2 + 2x^2 + 4y^2 + 8)      Factor by grouping:-

= 3[ x^2(y^2 + 2) + 4(y^2 + 2)]

= 3(x^2 + 4)(y^2 + 2)
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To answer that question
Mars2501 [29]
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Answer:

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Step-by-step explanation:

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