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Lelechka [254]
3 years ago
6

Factors of 3x^2y^2+6x^2+12y^2+24

Mathematics
1 answer:
ddd [48]3 years ago
4 0
Look for  the GCF

GCF = 3

so we have 

3 (x^2y^2 + 2x^2 + 4y^2 + 8)      Factor by grouping:-

= 3[ x^2(y^2 + 2) + 4(y^2 + 2)]

= 3(x^2 + 4)(y^2 + 2)
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Find the value of<br> 5!=<br> 7!=<br> 8!=
inessss [21]

Answer:

5i =  120\\ 7i  = 5040\\ 8 i= 40320

7 0
3 years ago
2/5x+y=3<br> solve the equation for y.
stira [4]
2/5x+y=3

-2/5x        -2/5x

y=-2/5x+3

Does y = to whole number or just like that? if it Whole number I will solve it tell me
3 0
3 years ago
I don’t understand this
svet-max [94.6K]

The answer is 1/20. This is probability. <u><em>probability is the chance of you picking a certain thing</em></u>. for example: You have 3 blue marbles, 6 red marbles, and 4 purple marbles. the probability of pick a blue marble is 3/13. A red would be 6/13, and a purple would be 4/13.

So what this is asking is what are the chances that something will happen over something will not happen. the said that "the probability that an event will not happen is P(E') = 19/20. if you are having a lot of trouble with this, try removing the events with something like marbles (Something you have done before) this tends to make it a little easier to read.

5 0
3 years ago
Write a inequality for the sentence then solve the inequality
Digiron [165]
It would be letter. b....
6 0
3 years ago
Read 2 more answers
For the functions f(x) = 5x − 3 and g(x) = x + 4, which composition produces the greatest output?
Zina [86]
You could actually find the compositions and thus have something to compare.  You haven't shared the list of possible answer choices.

(f+g)(x) = 5x - 3 + x + 4 = 6x + 1

(f-g)(x) = 5x - 3 - x - 4 = 4x - 7

(f*g)(x) = (5x-3)((x+4) = 5x^2 + 20x - 3x - 12 = 5x^2 + 17x - 12

There are also the quotient (f/g)(x) and the compositions f(g(x)) and g(f(x)).

WRite them out.

Then you could arbitrarily select x values, such as 2, 10, etc., subst. them into each composition and determine which output is greatest.

7 0
3 years ago
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