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sweet [91]
2 years ago
7

Simplify 3(8x+2y) A. 30x+y B. 24x+2y C. 24x+6y D. 30xy

Mathematics
1 answer:
Naddika [18.5K]2 years ago
4 0

Answer:

The choose C. 24x+6y

Step-by-step explanation:

3(8x + 2y)  = 24x + 6y

I hope I helped you^_^

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This should have been worth more points, but anyways, here are the answers. Please give thanks :)

1.)Y = 5 - 3X<span>
2.) Y= </span><span>3X - 4</span><span>
3.) Y = 7 - X
4.) Y = -5X 
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6.) Y = 5 -3X
7.) Y = 2 +</span>\frac{4}{3}<span>X
8.) </span>Y = \frac{1}{2}X - 3<span>
9.) Y= 2 - [</span>tex] \frac{2}{3} [/tex]<span>
10.) Y  = 1 - 5X
11.) Y = 2 - </span>\frac{1}{3}<span>X
12.) Y = -5 -2X
13.) Y = X - 6
14.) Y = </span>\frac{10}{3}<span> -2X
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5 0
3 years ago
Consider two independent tosses of a fair coin. Let A be the event that the first toss results in heads, let B be the event that
aliina [53]

Answer with Step-by-step explanation:

We are given that two independent tosses of a fair coin.

Sample space={HH,HT,TH,TT}

We have to find that A, B and C are pairwise independent.

According to question

A={HH,HT}

B={HH,TH}

C={TT,HH}

A\cap B={HH}

B\cap C={HH}

A\cap C={HH}

P(E)=\frac{number\;of\;favorable\;cases}{total\;number\;of\;cases}

Using the formula

Then, we get

Total number of cases=4

Number of favorable cases to event A=2

P(A)=\frac{2}{4}=\frac{1}{2}

Number of favorable cases to event B=2

Number of favorable cases to event C=2

P(B)=\frac{2}{4}=\frac{1}{2}

P(C)=\frac{2}{4}=\frac{1}{2}

If the two events A and B are independent then

P(A)\cdot P(B)=P(A\cap B)

P(A\cap)=\frac{1}{4}

P(B\cap C)=\frac{1}{4}

P(A\cap C)=\frac{1}{4}

P(A)\cdot P(B)=\frac{1}{2}\cdot \frac{1}{2}=\frac{1}{4}

P(B)\cdot P(C)=\frac{1}{4}

P(A)\cdot P(C)=\frac{1}{4}

P(A)\cdot P(B)=P(A\cap B)

Therefore, A and B are independent

P(B)\cdot P(C)=P(B\cap C)

Therefore, B and C are independent

P(A\cap C)=P(A)\cdot P(C)

Therefore, A and C are independent.

Hence, A, B and C are pairwise independent.

6 0
3 years ago
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