Hello Again! The answer would be C. (8,11)
To confirm we will plug the numbers x = 8, Y = 11
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2x - 5 = y
(2 x 8) - 5 = 11
16 - 5 = 11
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y = x + 3
11 = 8 + 3
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So now you can determine that the answer would be (8,11)
Answer:
Number of combinations = 56
Step-by-step explanation:
Points to remember
nCₐ = n!/(r!(n - r)!)
The given word is "FRIENDLY"
F R I E N D L Y is a 8 letter word.
<u>To find the number of combinations</u>
5 letters can be selected from 8 letter = 8C₅
8C₅ = 8!/(8 - 5)!5!
= 8!/3!5!
= (8 * 7 * 6* 5!)/(1 * 2 * 3 * 5!)
= 8 * 7
= 56
5 letter combinations can be created from the letters in the world “friendly = 56
12, 2, 4, and 7. The coefficients in the expression 12xy³+2x⁵y+4x⁵y²+7x⁵y are 12, 2, 4, and 7.
In order to solve this problem we have to know that the coefficients is a factor linked to a monomial. For example, the first monomial of the equation is 12xy³ the coeffcient of xy³ is 12.
Answer:
f(-2) = 0
Step-by-step explanation:
Given that:
f(x) = bx^2 + 32
f(2) = b(2)^2 + 32
f(2) = 4b + 32
f(2) = 4b = -32
f(2) = b = -32/4
f(2) = b = -8
Thus;
f(-2) = -8(-2)^2 + 32
f(-2) = -8(4) + 32
f(-2) = -32 + 32
f(-2) = 0
Answer: m = 0
Step-by-step explanation:
