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trasher [3.6K]
3 years ago
12

What number has 8 hundreds, 2 fewer tens than hundreds, and 2 fewer ones than hundreds

Mathematics
1 answer:
Anna71 [15]3 years ago
6 0

This number has a certain amount of hundreds, tens and ones. We know that there are 8 hundreds, so the number is like 8xy

Also, the tens are 2 fewer than the hundreds, so 2 fewer than 8, which is 6. The number is like 86y

The ones are also 2 fewer than the hundreds, so 2 fewer than 8, which is 6. So, the number is 866.

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Find the fifth term in the geometric
OlgaM077 [116]

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<h2>          a₅ = 162</h2>

Step-by-step explanation:

The nth term in the geometric sequence:  a_n=a_1\cdt r^{n-1}

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    a_5=a_1\cdot r^4=2\cdot3^4 = 2\cdot81=162

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Prove that sin²∅+cos²∅=1 ?​
sasho [114]

Step-by-step explanation:

Let ABC be a right angled triangle where there's a right angle in B . Let the measure of the angle BAC be ∅. So,

\sin(∅)  =  \frac{BC}{AC}

=  >   {\sin}^{2}∅ =  \frac{ {BC}^{2} }{ {AC}^{2} }

Also,

\cos(∅)  =  \frac{AB}{AC}

=  >  { \cos}^{2}∅ =  \frac{ {AB}^{2} }{ {AC}^{2} }

Now adding the values of sin^2∅& cos^2∅,

{ \sin}^{2} ∅ +  { \cos}^{2} ∅ =  \frac{ {BC}^{2} }{ {AC}^{2} }  +  \frac{ {AB}^{2} }{ {AC}^{2} }

=  >  { \sin}^{2} ∅ +  { \cos}^{2} ∅ =  \frac{ {AB}^{2} +  {BC}^{2}  }{ {AC}^{2} }

But we know that

{AC}^{2}  =  {AB}^{2}   +  {BC}^{2} by applying Pythagorean Theorem

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=  >  { \sin}^{2} ∅ +  { \cos}^{2} ∅ =   \frac{ {AC}^{2} }{ {AC}^{2} }  = 1

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2 years ago
7 x 9 = (1 x 10)-(7 x A)
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4 0
3 years ago
What is the surface area?
mash [69]

\large\bf{\underline{Answer:}}

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\large\bf{ = 3000 \:ft^2}

__________________________________________

\large\bf{\underline{Given:}}

  • A 3 dimensional figure with 5 sides
  • it has 3 rectangles with dimensions 28 ft and 25 ft
  • And 2 triangles with base =30 ft and height = 20 ft

\large\bf{\underline{To\: find:}}

  • Total surface area of figure

\large\bf{\underline{Therefore:}}

\bf{area \:of\: figure}

‎ㅤ{\bf = area \:of \:3\: rectangles + 2 \: triangles}

\large\bf{\underline{Formulas:}}

\boxed{\bf\pink{area\:of\: triangle= \frac{1}{2}\times base\times height}}

\boxed{\bf\pink{area\:of\: rectangle=length\times breadth}}

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\large\bf{= 3\times (28 \times 25 )+ 2(\frac{1}{2} \times 30 \times 20)}

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\large\bf{= 3 \times 800 + 2 \times 300}

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\large\bf{=2400+ 600}

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\large\bf{= 3000}

__________________________________________

\large\bf{\underline{Hence,}}

❒ Area of given figure

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\huge\mathfrak{= 3000\: ft^2}

5 0
3 years ago
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