For rigt triangle with legs legnth a and b and hypotnuse legnth c
a^2+b^2=c^2
we are given
larger leg is 3 longer than smaller leg
hypotnuse is 6 longer than smaller
find smaller
ok so
first pick a smaller leg
lets say b is smaller
longer leg is 3 more than shorter leg
a is 3 more than b
a=3+b
and
hypontuse is 6 more than shorter
c=6+b
sub 3+b for a and 6+b for c in oroiginal equation'
a^2+b^2=c^2
(3+b)^2+b^2=(6+b)^2
9+6b+b^2+b^2=36+12b+b^2
2b^2+6b^2+9=b^2+12b+36
minus (b^2+12b+36) from both sides
b^2-6b-27=0
factor
(b-9)(b+3)=0
set equal to zero
b-9=0
b=9
b+3=0
b=-3
fasle, legnths cannot be negative
answer is shorter side=9 cm
N = 2424 is the sample size (amount of cars being sampled)
df = degrees of freedom
df = n-1
df = 2424-1
df = 2423
Side Note: if there is a typo and the sample size should be n = 24 (instead of 2424), then the df would be df = n-1=24-1 = 23
Answer:
|x-5|=2
Step-by-step explanation:
1- Find the mid value between the given numbers 3 and 7
(3+7)/2= 10/2 = 5
2- Find the difference btween the mid value (5) and any of the two given numbers (3 or 7). Use the absolute value for the difference.
|5-3|= 2 or |7-5|=2
3- Arrange the absolute equation like this:
|x-mid value from step 1|= absolute difference from step 2
|x-5|=2
4- Double check the answer with the given values 3 and 7 using our equation |x-5|=2
|3-5|=2 correct
|7-5|=2 correct
Answer:
try the second one because it is the smallest and close togehet so maybe that means that the mean is closer to the number and it nots some outlier.
Step-by-step explanation:
