An experiment consists of drawing a marble out of a bag, observing the color, and then placing it back in the bag. Suppose the

Is 7/10 less than 2/4?

lilavasa [31]

Answer:

No

Step-by-step explanation:

7/10 is 0.7

2/4 is 0.5

0.7>05

5 0

3 years ago

Read 2 more answers

What are the latitude and longitude coordinates of the entrance to the Mount Rushmore parking area?Latitude: 43.8753972, Longitu

Alborosie

Answer:

The answer is already in the question. The coordinates of the entrance to the Mount Rushmore parking area are given by latitude 43.8753972 and longitude -103.4523083.

Step-by-step explanation:

I believe the person asking the question wants some other detail that s/he did not state explicitly.

8 0

3 years ago

Carlos is going for a walk. He walks for

seraphim [82]

I pretty sure the answer is 3.2 hours. I'm not completely sure though....

3 0

3 years ago

Driving on the highway, you can safely drive 60 miles per hour. "How far can you drive in ‘h' hours?" What is the range of the f

JulijaS [17]

Answer:

D.The distance you drive

Step-by-step explanation:

If you describe this situation as function, then it will look as:

f(h)= 60h
For h=1 you have f(1)= 60 miles
For h=2 you have f(2)= 120 miles etc.

The range of the function is the set of output values

In this case the range is the distance you drive

Correct option is D.

7 0

3 years ago

An industry representative claims that 10 percent of all satellite dish owners subscribe to at least one premium movie channel.

Greeley [361]

Answer: 1) 0.6561 2) 0.0037

Step-by-step explanation:

We use Binomial distribution here , where the probability of getting x success in n trials is given by :-

$P(X=x)=^nC_xp^x(1-p)^{n-x}$

, where p =Probability of getting success in each trial.

As per given , we have

The probability that any satellite dish owners subscribe to at least one premium movie channel. : p=0.10

Sample size : n= 4

Let x denotes the number of dish owners in the sample subscribes to at least one premium movie channel.

1) The probability that none of the dish owners in the sample subscribes to at least one premium movie channel = $P(X=0)=^4C_0(0.10)^0(1-0.10)^{4}$

$=(1)(0.90)^4=0.6561$

∴ The probability that none of the dish owners in the sample subscribes to at least one premium movie channel is 0.6561.

2) The probability that more than two dish owners in the sample subscribe to at least one premium movie channel.

= $P(X>2)=1-P(X\leq2)\\\\=1-[P(X=0)+P(X=1)+P(X=2)]\\\\= 1-[0.6561+^4C_1(0.10)^1(0.90)^{3}+^4C_2(0.10)^2(0.90)^{2}]\\\\=1-[0.6561+(4)(0.0729)+\dfrac{4!}{2!2!}(0.0081)]\\\\=1-[0.6561+0.2916+0.0486]\\\\=1-0.9963=0.0037$

∴ The probability that more than two dish owners in the sample subscribe to at least one premium movie channel is 0.0037.

8 0

3 years ago