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2 years ago

Write y=-3x^2+12x-21 in vertex form

2 answers:

6 0

The vertex form of any function is : f(x) = a(x-h)^2 + k
Hence the correct option would be: A): "-3(x-2)^2-9"

riadik2000 [5.3K]2 years ago

5 0

Complete the square:
y = 3x^2 - 12x + 4 
y = 3(x^2 - 4x) + 4 
y = 3(x^2 - 4x + 4 - 4) + 4 
y = 3(x^2 - 4x + 4) - 12 + 4 
y = 3(x - 2)^2 - 8

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Can someone please help me I really need this

svp [43]

Honestly i don’t really know but maybe a bar graph? you could put the monthly sales in the x axis and the earnings in the y axis. sorry

7 0

2 years ago

Mrs. Nevin is making a costume for a school play. She needs a piece of fabric that is greater than 1/2 of a yard but less than 5

Bumek [7]

Answer:

4/7 yards

Step-by-step explanation:

Given that :

Required fabric is > 1/2 but < 5/8

Let required fabric = x

Then ;

Converting the fractions to decimal :

1/2 = 0.5 ; 5/8 = 0.625

0.5 < x < 0.625

3/8 yards = 0.375 ;

4/7 yards = 0.571

3/7 yards = 0.429

2/4 yards = 0.5

0.5 < 0.571 < 0.625

From the options, only 4/7 yards satisfies the condition :

5 0

3 years ago

Find the value of X x=

Wewaii [24]

Answer:

x = 135°

Step-by-step explanation:

6 sided polygon = hexagon

The sum of the interior angles of a hexagon = 720°

⇒ 4x + 90 + 90 = 720

⇒ 4x = 720 - 90 - 90

⇒ 4x = 540

⇒ x = 540 ÷ 4

⇒ x = 135°

4 0

2 years ago

What is 2,345 rounded to the nearest 10

ser-zykov [4K]

2,350 Hope this helped

8 0

3 years ago

Read 2 more answers

A particle moves in the xy plane starting from time = 0 second and position (1m, 2m) with a velocity of v>=2i-4tj^

guapka [62]

Given :

A particle moves in the xy plane starting from time = 0 second and position (1m, 2m) with a velocity of v=2i-4tj .

To Find :

A. The vector position of the particle at any time t .

B. The acceleration of the particle at any time t .

Solution :

A )

Position of vector v is given by :

$d=\int\limits {v} \, dt\\\\d=\int\limits {(2i-4tj)} \, dt \\\\d=(2t)i+\dfrac{4t^2}{2}j\\\\d=(2t)i+(2t^2)j$

B )

Acceleration a is given by :

$a=\dfrac{dv}{dt}\\\\a=\dfrac{2i-4tj}{dt}\\\\a=\dfrac{2i}{dt}-\dfrac{4tj}{dt}\\\\a=0-4j\\\\a=-4j$

Hence , this is the required solution .

5 0

3 years ago