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3 years ago

If there are 16 values in a data set in order from smallest to largest, what is the median of the data set?

Mathematics

1 answer:

satela [25.4K]3 years ago

4 0

A.) The mean of the 8th and 9th values

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If Mitchell ate 45 hotdogs in 3 minutes at the annual hot dog eating contest. What is Mitchell’s unit rate?

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15 hotdogs per minute

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Which statement regarding triangle EFG are true? Select three options

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It is the first three options. A,B,C or 1,2,3

Step-by-step explanation:

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2 years ago

If electricity power failures occur according to a Poisson distribution with an average of 3 failures every twenty weeks, calcul

Wittaler [7]

Answer:

0.9898 = 98.98% probability that there will not be more than one failure during a particular week.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

3 failures every twenty weeks

This means that for 1 week, $\mu = \frac{3}{20} = 0.15$

Calculate the probability that there will not be more than one failure during a particular week.

Probability of at most one failure, so:

$P(X \leq 1) = P(X = 0) + P(X = 1)$

Then

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-0.15}*0.15^{0}}{(0)!} = 0.8607$

$P(X = 1) = \frac{e^{-0.15}*0.15^{1}}{(1)!} = 0.1291$

Then

$P(X \leq 1) = P(X = 0) + P(X = 1) = 0.8607 + 0.1291 = 0.9898$

0.9898 = 98.98% probability that there will not be more than one failure during a particular week.

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2 years ago

Identify the first operation needed in this equation

ruslelena [56]

Addition is the first step in solving the equation. Here is how to solve this problem:

x/3 - 3 = 11
+ 3 + 3
------------------------
x
(3) -------- = 14(3)
3

x = 42

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3 years ago

92 divided by 4 use partial and quotients to divide

kherson [118]

The partial quotient is 23

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