
if you solve those equations for "c" and "d" respectively, you'd get, well the Q point of c,d
For this case we have:
By trigonometric property we have:

Where:


Substituting:

Clearing x we have:

Thus, the equation is:
Answer:

Answer: ![\sqrt[5]{y}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7By%7D)
I realize its probably not the largest readable font. If you are having trouble reading it, it is the square root of y; however, there is a tiny little 5 in the upper left corner to indicate a fifth root. So you would read it out as "the fifth root of y"
The rule I'm using is
![x^{1/n} = \sqrt[n]{x}](https://tex.z-dn.net/?f=x%5E%7B1%2Fn%7D%20%3D%20%5Csqrt%5Bn%5D%7Bx%7D)
and the more general rule we could use is
![x^{m/n} = \sqrt[n]{x^m}](https://tex.z-dn.net/?f=x%5E%7Bm%2Fn%7D%20%3D%20%5Csqrt%5Bn%5D%7Bx%5Em%7D)
where m = 1. This rule helps convert from rational exponent form (aka fractional exponents) to radical form.
Answer:
25
Step-by-step explanation:
From the given information;
Numbers of posters that can be printed in an hour = no of impression/hour × no of plate utilized in each impression.
= 1000x
Thus, the required number of hours it will take can be computed as:

cost per hour = 125
If each plate costs $20 to make, then the total number of plate will equal to 40x
∴
The total cost can be computed as:


At C'(x) = 0




x = 25


where; x = 25

C''(x) = 1.6
Thus, at x = 25, C'' > 0
As such, to minimize the cost, the printer needs to make 25 metal plates.