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hram777 [196]
3 years ago
6

Linear or nonlinear!?

Mathematics
2 answers:
NeTakaya3 years ago
7 0

Answer:

nonlinear

Step-by-step explanation:

pshichka [43]3 years ago
6 0
Non linear because of the fact that the numbers aren’t equivalent
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Chelsea spent half of her weekly
Anvisha [2.4K]

Answer:

I believe it would be 16

Step-by-step explanation:

8 is half of 16 and if she had 8 dollars after spending half her allowance, she would've had 16 as her allowance

Final answer: Her allowance would be 16 dollars

3 0
2 years ago
Prove that the diagonals of a parallelogram bisect each other​
Nady [450]

Answer:

[ See the attached picture ]

The diagonals of a parallelogram bisect each other.

✧ Given : ABCD is a parallelogram. Diagonals AC and BD intersect at O.

✺ To prove : AC and BD bisect each other at O , i.e AO = OC and BO = OD.

Proof :\begin{array}{ |c| c |  c |  } \hline \tt{SN}& \tt{STATEMENTS} & \tt{REASONS}\\ \hline 1& \sf{In  \: \triangle ^{s}  \:AOB \: and \: COD  } \\  \sf{(i)}&  \sf{ \angle \: OAB =  \angle \: OCD\: (A)}& \sf{AB \parallel \: DC \: and \: alternate \: angles} \\  \sf{(ii)} &\sf{AB = DC(S)}& \sf{Opposite \: sides \: of \: a \: parallelogram} \\  \sf{(iii)} &\sf{ \angle \: OBA=  \angle \: ODC(A)} &\sf{AB \parallel \:DC \: and \: alternate \: angles} \\  \sf{(iv)}& \sf{ \triangle \:AOB\cong \triangle \: COD}& \sf{A.S.A \: axiom}\\ \hline 2.& \sf{AO = OC \: and \: BO = OD}& \sf{Corresponding \: sides \: of \: congruent \: triangle}\\ \hline 3.& \sf{AC \: and \: BD \: bisect \: each \: other \: at \: O}& \sf{From \: statement \: (2)}\\ \\ \hline\end{array}.          Proved ✔

♕ And we're done! Hurrayyy! ;)

# STUDY HARD! So, Tomorrow you can answer people like this , " Dude , I just bought this expensive mobile phone but it is not that expensive for me" [ - Unknown ] :P

☄ Hope I helped! ♡

☃ Let me know if you have any questions! ♪

\underbrace{ \overbrace  {\mathfrak{Carry \: On \: Learning}}} ☂

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

5 0
3 years ago
Answer with work pls
viktelen [127]

Answer:

50 students

Step-by-step explanation:

Hello!  

To solve this question, we would first need to look at the data. In this data, there are people who chose their favorite sport, and the number of people who chose that response. In order to solve the problem, we would have to find the ratio of how many people choose baseball over the other sports.

By this, we can add the number of students together. 30+10+5+15=60. Out of those 60 students, only 5 people chose baseball.

Since the ratio of the people who chose baseball is 5/60 (meaning that it is a 5/60 % chance someone would pick this sport), we would need to find the amount of people assumed to pick baseball in 600 student survey.

We can make a relationship with these two numbers.

\frac{5}{60} =\frac{x}{600}, since the ratio of the students who chose baseball remain the same.

You can see that the ratio on the denominators just add a zero on the bottom, so the top should add 0 as well, to get 50 for x, what we needed.

You can also solve that relationship by cross multiplication.

5(600)=x(60

3000=60x

50=x

Regardless, the answer is 50 students who would choose baseball in a 600 persons survey.

5 0
2 years ago
SOMEONE HELPFUL PLZ ANSWER!!!!!!!! WILL MARK BRAINLIEST!!!!!!!!!
Eva8 [605]

Answer:5,6 or 15,2

5x6x1.5 =45

15x2x1.5=45

3 0
2 years ago
Which situation could be modeled by the expression 3/4 ÷ 2 1/4?
vlabodo [156]

Answer:

\frac{1}{3}

Step-by-step explanation:

8 0
3 years ago
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