Angle m∠1 if formed by a tangent and secant intersecting outside of circle. The intercepted arcs are arc LK and arc JK.
Thus;
Angle formed by Tangent and secant
=1/2(DIFFERENCE of Intercepted Arcs)
m∠1=1/2(mJK-LK)
Answer: m∠1=1/2(mJK-KL)
Answer:
f(x)=(x-2)(x+2)(x-5)
Step-by-step explanation:
f(x)=x³-5x²+4x-20 1. Just group randomly
f(x)=x²(x-5)+4(x-5) 2. Factor the groupings
f(x)=(x²+4)(x-5)
<u>f(x)=(x-2)(x+2)(x-5)</u> 3. Factor the difference of two squares
The last expression: (16-8)x2+4=8x6=48
1/2(2x+6)
Substitute the one half to both of the numbers inside the parentheses.
1/2*2 is one which would just be x
1/2*6 is three
X+3
