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4 years ago

10

8+7-1=14 is the answer correct In the doubles minus one fact

2 answers:

Veronika [31]4 years ago

5 0

Answer:

Yup if you have 8+8=14 then 8+8-1=-1

nasty-shy [4]4 years ago

5 0

Answer:

yes the answer is correct

Step-by-step explanation:

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Jason paid a $100 start-up fee for his

katen-ka-za [31]

Answer:

b

Step-by-step explanation:

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3 years ago

How can you tell if three positive numbers form a<br> Pythagorean triple?

dusya [7]

Answer:

Since a Pythagorean triple is three positive integers a, b, and c such that (a^2)+(b^2)=(c^2), first take the sum of the squares of the two legs and make an estimate. For example, 3, 4, and 5 is a Pythagorean triple since 9+16=25.

Step-by-step explanation:

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4 years ago

Read 2 more answers

How many points are shared by two perpendicular lines? but two parallel lines?

ratelena [41]

Two perpendicular lines intersect once, to form a right angle. Therefore, on point is shared by two perpendicular lines. since parallel lines never touch, there are NO points shared between the two lines.

5 0

4 years ago

If cos0=3/5 and θ is in quadrant IV, sin20=?

alexandr402 [8]

Answer:

$sen(2\theta) =\frac{24}{25}$

Step-by-step explanation:

We know that $cos(\theta) =\frac{3}{5}$ and θ is in quadrant IV

To find $sin(\theta)$ we use the following identity

$sin^2(\theta)=1-cos^2(\theta)$

$cos^2(\theta) =\frac{3^2}{5^2}$

$cos^2(\theta) =\frac{9}{25}$

Then

$sin^2(\theta)=1-\frac{9}{25}$

$sin^2(\theta)=\frac{16}{25}$

$sin(\theta)=\±\sqrt{\frac{16}{25}}$

In the IV quadrant the $sin(\theta)> 0$ then we take the positive solution

$sin(\theta)=\frac{4}{5}$

Finally to find $sin(2\theta)$ we use the following identity

$sen(2\theta) = 2 sen(\theta) cos(\theta)$

Finally

$sen(2\theta) = 2*\frac{4}{5}*\frac{3}{5}$

$sen(2\theta) =\frac{24}{25}$

5 0

4 years ago

A welder is commissioned to make a gold metal cone from a cylindrical cone form, as shown. The height of the cylinder is 66 cent

Paraphin [41]

The shaded portion is equal to 13816cm^3

Data;

Height = 66cm
d = 20cm

<h3>Volume of a Cylinder</h3>

The formula of volume of a cylinder is given as

$v=\pi r^2 h$

Let's substitute the values and solve

$v = \pi r^2 h\\\\r = d/2\\d = 20\\r = 20/2 = 10cm\\v = 3.14 * 10^2 * 66\\v = 20724cm^3$

<h3>Volume of a Cone</h3>

The volume of a cone is given as

$v = 1/3 \pi r^2 h\\v = 1/3 * 3.14 * 10^2 * 66\\v = 6908cm^3$

The space remaining from creating the cone out of the cylinder is

$20724 - 6908 = 13816cm^3$

The shaded portion is equal to 13816cm^3

Learn more on volume of cone and cylinder here;

brainly.com/question/25920983

8 0

2 years ago