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Elanso [62]
3 years ago
12

What 2 elements that share the same properties and reactivity as the silicon?

Chemistry
1 answer:
VladimirAG [237]3 years ago
6 0
Two elements that have similar properties has silicon would be above or below silicon. they are germanium or antimony. 
   
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What is the chemical formula of the following compound
OLga [1]
A. C3H10 is the answer
6 0
3 years ago
53. A firefighter of mass 80 kg slides down a vertical pole
Zielflug [23.3K]

Answer:

Answer is given below:

Explanation:

<em>Given Data:</em>

mass = 80kg

acceleration = 4 ms

force = 800N

<em>Find out:</em>

friction = ?

<em>Formula</em><em>:</em>

F-friction = weight - f-net

<em>Solution:</em>

weight = (80)(10)

           = 800 N

F-net = ma =(80)(4) = 320N

F-friction = weight - F-net

               =800 N - 320N

               =480N

<em>Answer</em> :

Friction = 480 N

   

6 0
3 years ago
Question 2 (1 point)
babunello [35]

Answer:

o and cl

Explanation:

metals and nonmetals tend to form ionic bonds

7 0
3 years ago
One mole of an ideal gas doubles its volume in a reversible isothermal expansion. (a) What is the change in entropy of the gas?
Andre45 [30]

Explanation:

The given data is as follows.

       n = 1 mol,     V_{f} = 2V_{i}

       Q = 1500 J,      R = 8.314 J/mol k

(a)    \Delta S = \frac{dQ}{dT}

And, according to the first law of thermodynamics

                \Delta E_{int} = Q - W

And, in an isothermal process the change in internal energy of the gas is zero.

Hence,    0 = Q - W

or,             W = Q

Expression for work done in an isothermal process is as follows.

                   W = nRT ln \frac{V_{f}}{V_{i}}

As W = Q, Hence expression for Q will also be given as follows.

            Q = nRT ln \frac{V_{f}}{V_{i}}

Now,  

        \Delta S = \frac{nRT ln \frac{V_{f}}{V_{i}}}{T}

        [/tex]\Delta S = nR ln \frac{V_{f}}{V_{i}}[/tex]

                      = nR ln \frac{2V_{i}}{V_{i}}

                       = nR ln 2

                        = 1 \times 8.314 \times 0.693

                        = 5.76 J/K

Therefore, change in entropy is 5.76 J/K.

(b)    As,  Q = nRT ln \frac{V_{f}}{V_{i}}

                   = nRT ln \frac{2V_{i}}{V_{i}}

                   = nRT ln 2

           T = \frac{Q}{nR ln 2}

              = \frac{1500}{1 \times 8.314 ln 2}

              = 260.4 K

Therefore, temperature of the gas is 260.4 K.

7 0
3 years ago
In writing the complete ionic equation for the reaction (if any) that occurs when aqueous solutions of KOH and Mg(NO3)2 are mixe
Scilla [17]
C) Mg(OH)2
hope it helps
6 0
3 years ago
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