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-BARSIC- [3]
3 years ago
5

For y= 6x +(-2) what is y when x= -1

Mathematics
1 answer:
Anton [14]3 years ago
3 0

Answer:-8

Step-by-step explanation:-6+(-2)= -8

Adding up the negatives

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Combine like terms in expression below <br><br> 2f + 9e - f + 3e
Umnica [9.8K]

Answer:

12e + f

Step-by-step explanation:

2f - f = f

9e + 3e = 12

....

6 0
3 years ago
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What is the approximate area of the circle shown below 9.4 cm
aivan3 [116]

Answer:

Step-by-step explanation:

A= πr²

A= 22/7 multiply by the radius.

Divide 9.4cm by 2.

Whatever you get is your answer. Now take the formula I have shown you above. Whatever you get is your answer.

6 0
3 years ago
Joel is looking at a costs for using a gym. He could pay $50 per month for unlimited use or he could pay $12 per month plus $4 p
just olya [345]

Answer:

10

Step-by-step explanation:

4 x 10 = 40

40 + 12 = 52

6 0
3 years ago
field biologist collects 220 butterflies and moths. He collects 4 butterflies for every moth. How many butterflies and how many
ki77a [65]

Answer:

The number of butterflies he collects = 176

The number of moth he collects = 44

Step-by-step explanation:

This question has to do with ratio.

We are told in the question that:He collects 4 butterflies for every moth.

Hence, the ratio of

Butterflies : Moth

4 : 1

Sum of the proportion = 4 + 1 = 5

We are also told he has a total of 220 butterflies and moths.

Hence:

The number of butterflies he collects is calculated as

4/5 × 220 = 176 butterflies

The number of moth that he collects =

1/5 × 220 = 44 moth

3 0
3 years ago
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What is 3/4 of 16/21? worked out please
timofeeve [1]
Of means multiplication

So

\frac{3}{4} \sf{of}  \frac{16}{21}  =  \frac{3}{4} \times  \frac{16}{21}

And then simplify the numerator ad denominator

= \frac{3 \times 16}{4 \times 21} =  \frac{\ 1 \times 16}{4 \times 7}

And simplify the numerator and denominator again

= \frac{\ 1 \times 16}{4 \times 7} = \frac{\ 1 \times 4}{1 \times 7}

And we are finally left with the answer which is \frac{4}{7}
5 0
3 years ago
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