Problem 1
Draw a straight line and plot P anywhere on it. Use the compass to trace out a faint circle of radius 8 cm with center P. This circle crosses the previous line at point Q.
Repeat these steps to set up another circle centered at Q and keep the radius the same. The two circles cross at two locations. Let's mark one of those locations point X. From here, we could connect points X, P, Q to form an equilateral triangle. However, we only want the 60 degree angle from it.
With P as the center, draw another circle with radius 7.5 cm. This circle will cross the ray PX at location R.
Refer to the diagram below.
=====================================================
Problem 2
I'm not sure why your teacher wants you to use a compass and straightedge to construct an 80 degree angle. Such a task is not possible. The proof is lengthy but look up the term "constructible angles" and you'll find that only angles of the form 3n are possible to make with compass/straight edge.
In other words, you can only do multiples of 3. Unfortunately 80 is not a multiple of 3. I used GeoGebra to create the image below, as well as problem 1.
Answer:
We can divide the pentagon (5 sides) into five inscribed triangles with central vertex angles of 72 degrees. 360 degrees ÷ 5 = 72 degrees....complete rotation is 360 degrees So each rotation of the pentagon of 72 degrees will be identical
Step-by-step explanation:
hope it helps :))
Answer:
you’ve tried and have not won, Never stop for crying; All that’s good and great is done Just by patient trying. Though young birds, in flying, fall, Still their wings grow stronger, And the next time they can keep Up a little longer. Though the sturdy oak has known Many a wind that bowed her, She has risen again and grown Loftier and prouder. If by easy work you’re beat, Who the more will prize you? Gaining victory from defeat, That’s the test that tries you
The given scale for the map means that a distance of 1 cm between two locations on the map corresponds to a real distance between them of 600,000 cm = 6 km.
So, if the distance between two places in reality is 87 km, on the map this would be represented by a distance of 14.5 cm, since
87 = 84 + 3
87 = 6 • 14 + 6 • (1/2)
87 = 6 • (14 + 1/2)