Answer:
whats the question
dummy
Step-by-step explanation:
Answer:
x = 
Step-by-step explanation:
Given
+ 
- 
= 
Multiply through by wxyz to clear the fractions
2xyz + 3wyz - 4wxz = wxy ( subtract wxy from both sides )
2xyz + 3wyz - 4wxz - wxy = 0 ( subtract 3wyz from both sides )
2xyz - 4wxz - wxy = - 3wyz ( factor out x from each term on the left side )
x(2yz - 4wz - wy) = - 3wyz ( divide both sides by (2yz - 4wz - wy )
x = 
( multiply numerator/ denominator by - 1 )
x =
The answer is c. 30000 dollars
Answer:
x = 4 , y = 1
Step-by-step explanation:
3x + 2y = 14 → (1)
x + y = 5 → (2)
Multiplying (2) by - 2 and adding to (1) will eliminate the y- term
- 2x - 2y = - 10 → (3)
Add (1) and (3) term by term to eliminate y
x = 4
Substitute x = 4 into (2) and evaluate for y
4 + y = 5 ( subtract 4 from both sides )
y = 1
Answer:
∠STU = 69°
Step-by-step explanation:
The angle with vertex T is called an "inscribed angle." It intercepts arc SU. The relationship you are asked to remember is that the measure of the inscribed angle (T) is half the measure of the arc SU.
Point V is taken to be the center of the circle. The angle with vertex V is called a "central angle." It also intercepts arc SU. The relationship you are asked to remember is that the measure of the central angle (V) is equal to the measure of arc SU.
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Using these two relationships together, we realize angle V is twice the measure of angle T:
∠SVU = 2×∠STU
18x +12° = 2(18x -57°) . . . . . . relationship between the marked angles
18x +12° = 36x -114° . . . . . eliminate parentheses
126° = 18x . . . . . . . . . . . add 114°-18x
∠STU = 18x -57° = 126° -57°
∠STU = 69°
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<em>Additional comment</em>
You may notice we did not solve for x. We only needed to know the value of 18x, so we stopped when we found that value. (Actually, we only need the value of 18x-57°. See below.)
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<em>Alternate solution</em>:
(18x +12°) -(18x -57°) = 18x -57° . . . . . . . subtract 18x -57° from both sides of the first equation.
69° = 18x -57° . . . . . simplify. This is the answer to the problem.
