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3 years ago

If 100c^2 has a value of 4950 what is the value of 100c98

Mathematics

1 answer:

N76 [4]3 years ago

6 0

Answer:

$100(49.5)^{49}$

Step-by-step explanation:

Let's solve $100c^2=4950$

Divide both sides by 100:

$c^2=49.5$

Take the square root of both sides:

$c=\sqrt{49.5}$ (I did not keep the negative value because it doesn't matter since we are only considering even powers of $c$ .)

So now let's plug it into:

$100c^{98}$

$100(\sqrt{49.5})^{98}$

$100(49.5)^{49}$

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I please need help solving for x .

Alekssandra [29.7K]

Answer:

16=x

Step-by-step explanation:

So, The angle is 180 degrees

180-87=93

93=(6x-3)

Add 3 to both sides

96=6x

Divide 6 on both sides

16=x

7 0

3 years ago

Read 2 more answers

ANSWER FAST ITS URGENT

Vlad1618 [11]

Answer:

9) 6.3 units

11) n=6√2 and m=12,

10) m=6√3, n=6

12) 330.6 ft

Step-by-step explanation:

1) The Pythagoras Theorem says that, the square of the hypotenuse is the sum of the squares of the two shorter legs.

Let the missing side, which is the hypotenuse be x.

Then

${x}^{2} = {2}^{2} + {6}^{2}$

${x}^{2} = 4 + 36$

${x}^{2} = 40$

$x = \sqrt{40}$

$x = 6.3$

The missing side is 6.3 units to the nearest tenth.

2) This is an isosceles right triangle.

This implies that, the two legs are equal.

$n = 6 \sqrt{2}$

The hypotenuse can be found using Pythagoras Theorem.

${m}^{2} = {(6 \sqrt{2} )}^{2} + {(6 \sqrt{2} )}^{2}$

${m}^{2} = 36(4)$

$m = \sqrt{36 \times 4} = 6 \times 2 = 12$

3) The side lengths of 30°-60°-90° are in the ratio, 2x,x√3,x

From the diagram, the hypotenuse is 12, therefore the other two legs are

$n = \frac{1}{2} (12) = 6$

and

$m = 6 \sqrt{3}$

4) The height of the monument is 115 feet, the hypotenuse is 350.

By Pythagoras Theorem,

${x}^{2} + {115}^{2} = {350}^{2}$

${x}^{2} = {350}^{2} - {115}^{2}$

${x}^{2} = 109275$

$x = \sqrt{109275} = 330.6 ft$

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4 years ago

A small military base housing 1,000 troops, each of whom is susceptible to a certain virus infection. Assuming that during the c

slava [35]

Answer:

$I=\frac{1000}{exp^{0,806725*t-0.6906755}+1}$

Step-by-step explanation:

The rate of infection is jointly proportional to the number of infected troopers and the number of non-infected ones. It can be expressed as follows:

$\frac{dI}{dt}=a*I*(1000-I)$

Rearranging and integrating

$\frac{dI}{dt}=a*I*(1000-I)\\\\\frac{dI}{I*(1000-I)}=a*dt\\\\\int\frac{dI}{I*(1000-I)}=\int a*dt\\\\-\frac{ln(1000/I-1)}{1000}+C=a*t$

At the initial breakout (t=0) there was one trooper infected (I=1)

$-\frac{ln(1000/1-1)}{1000}+C=0\\\\-0,006906755+C=0\\\\C=0,006906755$

In two days (t=2) there were 5 troopers infected

$-\frac{ln(1000/5-1)}{1000}+0,006906755=a*2\\\\-0,005293305+0,006906755=2*a\\a = 0,00161345 / 2 = 0,000806725$

Rearranging, we can model the number of infected troops (I) as

$-\frac{ln(1000/I-1)}{1000}+0,006906755=0,000806725*t\\\\-\frac{ln(1000/I-1)}{1000}=0,000806725*t-0,006906755\\-ln(1000/I-1)=0,806725*t-0.6906755\\\\\frac{1000}{I}-1=exp^{0,806725*t-0.6906755} \\\\\frac{1000}{I}=exp^{0,806725*t-0.6906755}+1\\\\I=\frac{1000}{exp^{0,806725*t-0.6906755}+1}$

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3 years ago

one morning it was- 9°F in Columbus, Ohio and -7°F in Pittsburgh,Pennsylvania. was it warmer in Columbus or Pittsburgh

Klio2033 [76]

Pittsburgh because -9°F is colder than -7<span>°F</span>

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3 years ago

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If |u| = 10, |v| = 8, and the angle formed between them is 60°, then u · v = ?

Gre4nikov [31]

U . v = |u| . |v| cos 60 = 10 * 8 * 0.5 = 40 This is called the scalar (or dot) product.

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3 years ago