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kvasek [131]
3 years ago
14

Find the probability.

Mathematics
2 answers:
stepan [7]3 years ago
7 0

Answer:

6/25

Step-by-step explanation:

P(First Fruit is Apple, Second Fruit is peach)

= (4/10)(6/10)

= <u>6</u><u>/</u><u>2</u><u>5</u>

IrinaVladis [17]3 years ago
4 0
Chance of getting Apple is 4/10. Chance of getting peach is 6/10. 4/10 x 6/10 is 24/100. I’m not 100% sure about this one though.
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A printer shop purchases a new printer fro $25,000
the equipment depreciates at a rate of 5% each year
the relationship between the value of the printer, y, and the year number, x can represented by the equation y=25,000*0.95^x
year 1: $23,750
year 2: $22,562.50
year 3: $21,434.38  
8 0
3 years ago
Sandy works at a clothing store. She makes $8 per hour plus earns 15% commission on her sales. She worked 80 hours over the last
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4 0
3 years ago
Edison Research gathered exit poll results from several sources for the Wisconsin recall election of Scott Walker. They found th
olchik [2.2K]

Answer: Our required probability is 0.515.

Step-by-step explanation:

Since we have given that

Probability that the respondents voted in favor of Scot Walker P(F) = 56%

Probability that the respondent voted in not favor of Scot Walker = 100-56 = P(F')=44%

Probability of those who did vote in favor had a college degree = 36% = P(C|F)

Probability of those who did vote against had a college degree = 44% = P(C|F')

So, we will use "Conditional Probability":

probability that he voted in favor of Scott Walker given that they had a college degree is given by

P(F|C)=\dfrac{0.56\times 0.36}{0.56\times 0.36+0.44\times 0.43}\\\\P(F|C)=0.515

Hence, our required probability is 0.515.

7 0
3 years ago
A recipe for peanut butter cookies calls for 1 cup of sugar, 1 cup of chunky peanut butter, and 1 medium egg. The recipe yields
hichkok12 [17]

Answer:

10 batches - they only have 10 eggs, so they can't make any more batches without them

4 0
3 years ago
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Shkiper50 [21]
To find the inverse, we swap the variables y and x, then solve for the new y.

3a. y=\frac{3}{x-1}

Swapping the variables: x=\frac{3}{y-1}
Solving for y: x(y-1)=3 \\ y-1= \frac{3}{x} \\ y=1+\frac{3}{x}
The domain of this inverse is x ≠ 0.
3b. y=x^2-1

Swapping: x = y^2 - 1
Solving for y: y^2 = x + 1 \\ y = \sqrt{x+1}
The domain of this inverse is x ≥ -1.
3c. y=\sqrt[3]{\frac{x-7}{3}}
Swapping: x=\sqrt[3]{\frac{y-7}{3}}
Solving for y: x^3=\frac{y-7}{3} \\ y-7=3x^3 \\ y=3x^3+7
The domain of this inverse is all real numbers.
4a. y=\frac{3}{x-1}, y=1+\frac{3}{x}
y=\frac{3}{(1+\frac{3}{x})-1} \\ y=\frac{3}{(\frac{3}{x})} \\ y=x
y=1+\frac{3}{(\frac{3}{x-1})} \\ y = 1+(x-1) \\ y = x

4c. y=\sqrt[3]{\frac{x-7}{3}}, y=3x^3+7
y=\sqrt[3]{\frac{(3x^3+7)-7}{3}} \\ y=\sqrt[3]{\frac{3x^3}{3}} \\ y=\sqrt[3]{x^3} \\ y=x
y=3(\sqrt[3]{\frac{x-7}{3}})^3+7 \\ y = 3({\frac{x-7}{3}})+7 \\ y = (x-7)+7 \\ y=x



3 0
3 years ago
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