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4 years ago

The area of a square photo is 9 square inches. how long is each side of the photo?

Mathematics

2 answers:

Harrizon [31]4 years ago

4 0

Hello.

Each side I believe would be 3 in.

Hope it helps!

sineoko [7]4 years ago

4 0

Each side is 2.25 in

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X2 +10x=39 , how do i solve or whats the answer

stealth61 [152]

Answer:

x = 3,-13 :)

Step-by-step explanation:

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3 years ago

Help me solve this plz

Reptile [31]

Answer:

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3 years ago

Complete the factored form of the algebraic expression 18a + 3 = 3( _____+_____)

rodikova [14]

So to factorise an expression, you put it into a form where if you expanded the brackets, you'd get the given expression.. if that makes sense. Therefore, you need to multiply the 3 by something to get 18a, and so the first term is 6a. You don't need to multiply 3 by anything to get 3, so the second term is 1. The final result looks like:
3(6a + 1)

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3 years ago

Anna [14]

Answer:

15% if I remember correctly

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3 years ago

Two fractions have denominators of x^2+ 6x + 9 and x^2. What is the Least Common Denominator?

Gala2k [10]

SOLUTION

Write out the denominator of the fraction, we have

$\begin{gathered} x^2+6x+9 \\ \text{And } \\ x^2-9 \end{gathered}$

We want to obtain the least common denominator.

To do this, we need to factorize each of the expression given

$\begin{gathered} x^2+6x+9 \\ =x^2+3x+3x+9 \\ =x(x+3)+3(x+3) \\ =(x+3)(x+3) \end{gathered}$

Then we factorise the other fraction using difference of two square

$\begin{gathered} a^2-b^2=(a-b)(a+) \\ \text{Then} \\ x^2-9=x^2-3^2 \\ =(x-3)(x+3) \end{gathered}$

The the factorise expression becomes

$(x+3)(x+3)\text{ and (x-3)(x+3)}$

To obtain the least common denominator, we select the common factor and the product of the other factor,

Hence

$\begin{gathered} \text{common factor=(x+3)} \\ \text{The other factors are (x-3)(x+3)} \\ \text{Then } \\ \text{Least co}mmon\text{ denominator becomes } \\ (x+3)(x-3)(x+3) \end{gathered}$

Thus

The Least Common Denominator is (x +3)(x+3)(x-3) (Last Option )

5 0

1 year ago