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11111nata11111 [884]
2 years ago
15

A certain lottery has numbers. In how many different ways can of the numbers be​ selected?

Mathematics
1 answer:
Zepler [3.9K]2 years ago
5 0

When a certain lottery has 33 numbers. the different ways can 6 of the numbers be selected is 1107568 ways.

<h3>How to calculate the value?</h3>

From the information, the certain lottery has 33 numbers and we want to know how many different ways can 6 of the numbers be selected.

It should be noted that in this case, we will use combination. This will be illustrated thus:

n = 33

p = 6

Therefore, the combination will be:

C(33, 6)

= 33! / (33 - 6)! × 6!

= 1107568 ways

Learn more about combinations on:

brainly.com/question/4658834

#SPJ1

A certain lottery has 33 numbers. In how many different ways can 6 of the numbers be selected?

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We want to get the probability of randomly picking two candles of the same color. We will see that this probability is 0.6

First, the thing that we know is that there are 16 candles, 12 red and 4 yellow.

The probability of getting a red candle in the first pick is given by the quotient between the number of red candles and the total number of candles:

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The probability of getting another red candle is computed in the same way, but now there are 11 red candles and 15 candles in total:

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The joint probability is given by the product of the two individual probabilities:

P = p*q = (3/4)*(11/15) = 33/60 = 0.55

Now we must do the same thing but with the yellow candles, the probability of getting a yellow candle in the first draw is:

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For the second candle we have:

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The joint probability is:

P' = p*q = (1/4)*(1/5) = 1/20 = 0.05

Then the probability of getting two candles of the same color is the sum of the two above:

P'' = 0.55 + 0.05 = 0.6

If you want to learn more about probabilities, you can read:

brainly.com/question/251701

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