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11111nata11111 [884]
1 year ago
15

A certain lottery has numbers. In how many different ways can of the numbers be​ selected?

Mathematics
1 answer:
Zepler [3.9K]1 year ago
5 0

When a certain lottery has 33 numbers. the different ways can 6 of the numbers be selected is 1107568 ways.

<h3>How to calculate the value?</h3>

From the information, the certain lottery has 33 numbers and we want to know how many different ways can 6 of the numbers be selected.

It should be noted that in this case, we will use combination. This will be illustrated thus:

n = 33

p = 6

Therefore, the combination will be:

C(33, 6)

= 33! / (33 - 6)! × 6!

= 1107568 ways

Learn more about combinations on:

brainly.com/question/4658834

#SPJ1

A certain lottery has 33 numbers. In how many different ways can 6 of the numbers be selected?

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{362 – [63 + (48 ÷ 2) x 2]} + 3(9 +4)
Julli [10]

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Step-by-step explanation:

<u>Solving with one operation at each step:</u>

  • {362 – [63 + (48 ÷ 2) x 2]} + 3(9 +4) =
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6 0
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Read 2 more answers
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