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WINSTONCH [101]
3 years ago
14

5!(3!)/4! all include factorials. what to do?

Mathematics
1 answer:
shtirl [24]3 years ago
6 0
5! Is the same as 5x4x3x2x1 and 4! Is the same as 4x3x2x1 because 4! Is in the denominator it cancels the 4x3x2x1 in the numerator and you are left with 5x(3!) witch is the same a 5x3x2x1. The answer=30
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I NEED HELP FAST PLEASE!
Zinaida [17]

Answer:

Step-by-step explanation:

1.5 + 5 = 6.5

hope it helps

7 0
3 years ago
Check that x=2 and y=5 is a solution of both equations below:<br> X+2y=12<br> 3x+6y=36 *
melamori03 [73]

Answer:

yes

Step-by-step explanation:

Substitute x = 2 and y = 5 into the left side of the equations and if equal to the right side then they are a solution.

x + 2y = 2 + 2(5) = 2 + 10 = 12 ← True

3x + 6y = 3(2) + 6(5) = 6 + 30 = 36 ← True

Thus x = 2, y = 5 is a solution to both equations

7 0
3 years ago
Read 2 more answers
Construct an inscribed circle in triangle PQR by finding the incenter of the triangle.
hodyreva [135]

Answer:

Check it below

Step-by-step explanation:

Hello!

By definition, the intercept of the 3 bisectors, within a triangle is the Incenter. So let's get started, by tracing three bisectors.

In the triangle PQR::

  1. Use a compass, open its legs with a little more than half of \overline{PQ}  . Place the needle point in the vertex of P. Mark!
  2. Do the same, placing the needle point in Q, following \overline{QP} direction. Mark
  3. Repeat it with the other triangle's line segment, namely:

\overline {QR},\:\overline{PR}

   4.Trace with a ruler, from each intersection point a line. You'll trace three lines then.

    5. Place the compass' needle point in this intersection point, (inside the triangle) with a hinge up to the triangle side, draw the circle inscribed.

 

7 0
3 years ago
Two skaters are practicing at the same time on the same rink. A coordinate grid is superimposed on the ice. One skater follows t
myrzilka [38]

Answer:

The skaters will collide at the points;

(2,28) and (4,24)

Step-by-step explanation:

The points they might collide will be the points when both y are equal;

-2x + 32 = -2x^2 + 18x

2x^2 -18x -2x + 32 = 0

2x^2 -20x + 32 = 0

2x^2 - 16x - 4x + 32 = 0

2x(x -8) -4( x -8) = 0

(2x -4)(x -8) = 0

2x = 4 or x = 8

x = 4/2 or x = 8

hence; x = 2 or 8

Now let’s get the y value

at x = 2, just substitute into any of the 2

y = -2x + 32

y = -2(2) + 32

y = -4 + 32 = 28

at x = 4

y = -2(4) + 32

y = -8 + 32

y = 24

The points that they will collide are;

(2,28) and (4,24)

4 0
3 years ago
Betty's height is 2/3 of Jinlan's height. Find the ratio of Betty's height to Jinlan's height.
nasty-shy [4]
Betty's height versus Jinlan's height is 2:3
3 0
3 years ago
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