ΔAOB is a right angled triangle. Therefore the Pythagorean Theorem applies in this situation.
θ is the angle from a standard position of the line OA
The length of the y component is √(1-0)2 +(-3-(-3))2] =√(12+ 02) = 1 A(-3,1) to B(-3,0) which is opposite
Then the length of the x-component is √[(-3-0)2 +(0-0)2] = √(9+0)= 3 B(-3,0) to O(0,0) which is adjacent
The length of vector OA is √[(-3-0)2 + (1-0)2] = √(9+1) = √(10) A(-3,1) to O(0,0) which is the hypotenuse of the triangle
θ = 180 - α
sinθ = sin(180-α) = opposite/hypotenuse = 1/√10
cosθ = adjacent/hypotenuse = -3/√10
tanθ = opposite/adjacent = 1/-3 = -1/3
α= arcsin(1/√10) ≈ 18
θ =180 -18 ≈162
Answer:
Well t find the area of a triangle, you need to multiple Base x height. That gives you 43.56. Now you divide by 2. So the end product will give you 21.78. Those same rules apply to every time you are finding the area of a triangle.
Step-by-step explanation:
Y - y1 = m(x - x1)
slope(m) = -3
(2,-1)...x1 = 2 and y1 = -1
now we sub....pay attention to ur signs
y - (-1) = -3(x - 2)....not done yet
y + 1 = -3(x - 2) <===
Answer:
Step-by-step explanation:
Given: The triangle with coordinate A(4,6), B(2,-2) and C(-2,-4). D is the mid point of AB and E is the mid point of AC.
To prove: DE is parallel to BC.
Construction: Join DE.
Proof: If we prove the basic proportionality theorem that is 
, then it proves that DE is parallel to BC.
Now, Mid Point D has coordinates=
and Mid Point E has coordinates=
Now, AD= 
DB=
AE=
EC=
Now,
=
Hence,
Thus, By basic proportionality theorem, DE is parallel to BC.
