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Sedbober [7]
4 years ago
9

What i the aswer of ×^2+5×-24=0

Mathematics
2 answers:
NNADVOKAT [17]4 years ago
3 0
<span>×^2+5×-24=0
(x+8)(x-3) = 0
x+8 = 0, x = -8
x - 3 = 0, x = 3
answer: </span>x = -8 and x =3
Katarina [22]4 years ago
3 0
<span>Simplifying x2 + 5 + -24 = 0 Reorder the terms: 5 + -24 + x2 = 0 Combine like terms: 5 + -24 = -19 -19 + x2 = 0 Solving -19 + x2 = 0 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '19' to each side of the equation. -19 + 19 + x2 = 0 + 19 Combine like terms: -19 + 19 = 0 0 + x2 = 0 + 19 x2 = 0 + 19 Combine like terms: 0 + 19 = 19 x2 = 19 Simplifying x2 = 19 Take the square root of each side: x = {-4.358898944, 4.358898944}..................</span>
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Answer:

a) n=\frac{0.5(1-0.5)}{(\frac{0.02}{1.96})^2}=2401  

And rounded up we have that n=2401

b) n=\frac{0.07(1-0.07)}{(\frac{0.02}{1.96})^2}=625.22  

And rounded up we have that n=626

And we see that if we have previous info about p the sample size varies a lot.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

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In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

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The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.02 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

Since we don't have prior information about the population proportion we can use ase estimator \hat p =0.5. And replacing into equation (b) the values from part a we got:

n=\frac{0.5(1-0.5)}{(\frac{0.02}{1.96})^2}=2401  

And rounded up we have that n=2401

Part b

For thi case the estimator for p is \hat p =0.07

n=\frac{0.07(1-0.07)}{(\frac{0.02}{1.96})^2}=625.22  

And rounded up we have that n=626

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