Answer:
The approximate distance is 15416 miles....
Step-by-step explanation:
We have given:
A satellite is 19,000 miles from the horizon of earth.
The radius is 4,000 miles.
Lets say that BC =x
AO = OB = 4,000 miles
AC = 19,000 miles
The tangent from the external point forms right angle with the radius of the circle.
So in ΔABC
(OC)² = (AC)²+(OA)²
where OC = x+4000
AC = 19,000
OA = 4000
Therefore,
(x+4000)² = (19,000)² +(4,000)²
Take square root at both sides:
√(x+4000)² = √(19,000)² +(4,000)²
x+4000 =√361000000+16000000
x+4000 = √377000000
x+4000 = 19416.48
x= 19416.48 - 4000
x = 15416.48
Therefore the approximate distance is 15416 miles....
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Answer:
b. 4 (7 + 6)
Step-by-step explanation:
Finding the GCF between 28 and 24:
We keep dividing while both numbers can be divided by the same factor. So
28 - 24|2
14 - 12|2
7 - 6
There is no number for which 7 and 6 are both divisible by, so the GCF between 28 and 24 is 4.
Simplifying in function of the GCF:
Now, we put 4 in evidence, and divide the rest of the expression by 4. So
The answer is given by option b.
