Answer:Choice A) All points with an x-value of 3 are located in Quadrant I.
We can show it is false through the use of a counter example. For instance, the point (3, -5) is not in quadrant 1, but rather in quadrant 4.
We would need to say "all points with x value 3 and positive y value" to ensure the point is in quadrant 1.
Step-by-step explanation:
37x + 41y = 70 --- R¹
41x + 37y = 86 --- R²
R¹ + R² : 78x + 78y = 156
78(x + y) = 156
x + y = 2 --- R³
R¹ - R² : -4x + 4y = -16
4(y - x) = -16
y - x = -4 --- R⁴
R³ + R⁴ : 2y = -2
y = -1
R³ - R⁴ : -2x = -6
x = 3
Hello :
<span>y = –2x – 1....(1)
y = 3x–1.....(2)
by (1) and (2) : 3x-1 = -2x-1
5x =0
x =0 ....(</span><span>the x-coordinates of the solutions)</span>
Answer:
The x-intercept is 2.
Step-by-step explanation:
![2 \sqrt[3]{x - 10} + 4 = 0](https://tex.z-dn.net/?f=2%20%5Csqrt%5B3%5D%7Bx%20-%2010%7D%20%20%2B%204%20%3D%200)
![2 \sqrt[3]{x - 10} = - 4](https://tex.z-dn.net/?f=2%20%5Csqrt%5B3%5D%7Bx%20-%2010%7D%20%20%3D%20%20-%204)
![\sqrt[3]{x - 10 } = - 2](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7Bx%20-%2010%20%7D%20%20%3D%20%20-%202)
120 ft... a flat vertical line is 180 degrees, and since this is a 30,60,90 triangle, your equation is... 180-60=distance John is to the base
