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Elza [17]
2 years ago
13

Find (x³+x²-20x+24) divided by (x-3)​

Mathematics
1 answer:
Rus_ich [418]2 years ago
3 0

Answer:

\frac{x^3 + x^2 -20x + 24}{x-3} = x^2 +4x-8

Step-by-step explanation:

Given;

p(x) = x³ + x²- 20x + 24

factor of p(x) = x-3

Apply long division method;

                 x² + 4x - 8

              ------------------------------

x - 3     √ x³ + x²- 20x + 24

             -( x³ - 3x²)

              -------------------------------

                      4x² - 20x + 24

                    -(4x²  -12x )

             -------------------------------

                               -8x  + 24

                             - (-8x  + 24)

              -----------------------------------------

                                       0

thus, \ \frac{x^3 + x^2 -20x + 24}{x-3} = x^2 +4x-8

                       

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Please help me asap<br>​
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Answer:

Step-by-step explanation:

From the picture attached,

∠4 = 45°, ∠5 = 135° and ∠10 = ∠11

Part A

∠1 = ∠4 = 45°  [Vertically opposite angles]

∠1 + ∠3 = 180° [Linear pair of angles]

∠3 = 180° - ∠1

     = 180° - 45°

     = 135°

∠2 = ∠3 = 135°  [Vertically opposite angles]

∠8 = ∠5 = 135° [Vertically opposite angles]

∠5 + ∠6 = 180° [Linear pair of angles]

∠6 = 180° - 135°

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∠7 = ∠6 = 45° [Vertically opposite angles]

By triangle sum theorem,

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45° + 45° + m∠10 = 180°

m∠10 = 180° - 90°

m∠10 = 90°

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Part B

1). ∠1 ≅ ∠4  [Vertically opposite angles]

2). ∠7 + ∠5 = 180° [Linear pair]

3). ∠9 + ∠10 = 180° [Linear pair]

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3 years ago
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