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Naddika [18.5K]
3 years ago
6

When you draw a multi-phase sample ____. Group of answer choices

Mathematics
1 answer:
notsponge [240]3 years ago
8 0

Answer:

The correct answer is letter "B": You use information from a first sample for collecting a subsequent subsample for further study.

Explanation:

Multi-phase sampling is a strategy by which a large number of data under study is taken, then a subsample of that pool is taken, and after that, another smaller subsample is taken in an attempt to count with samples that best might represent the whole population. Usually, the process takes collecting two different samples, but it can be applied as many times as necessary.

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Evaluate the square root of 121.
Vanyuwa [196]

Answer:

It's 11

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
What is 635/72=-5/2(-11/4+x)
Ahat [919]

635/72=-5/2(-11/4+x)

distribute

635/72 = -5/2 * -11/4 - 5/2x

635/72 = 55/8 -5/2 x

multiply each side by 72 to clear the fractions

72*635/72 = 72*(55/8 - 5/2 x)

distribute

635 = 72* 55/8 - 72* 5/2 x

635 = 495 - 180x

subtract 495 from each side

140 = -180 x

divide by -180

-140/180 = x

-14/18 =x

-7/9 =x

5 0
3 years ago
There are exactly five rows with two primes in them. Which rows are these?
Neko [114]
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8 0
3 years ago
A welder produces 7 welded assemblies during the first day on a new job, and the seventh assembly takes 45 minutes (unit time).
likoan [24]

Answer:

(a). 72.9%.

(b). 13.6 hr.

Step-by-step explanation:

So, we are given the following data or parameters or information which is going to assist us in solving this question/problem;

=> "A welder produces 7 welded assemblies during the first day on a new job, and the seventh assembly takes 45 minutes (unit time). "

=> The worker produces 10 welded assemblies on the second day, and the 10th assembly on the second day takes 30 minutes"

So, we will be making use of the Crawford learning curve model.

T(7) + 10 = T (17) = 30 min.

T(7) = T1(7)^b = 45.

T(17 ) = T1(17)^b = 30.

(T1) = 45/7^b = 30/17^b.

45/30 = 7^b/17^b = (7/17)^b.

1.5 = (0.41177)^b.

ln 1.5 = b ln 0.41177.

0.40547 = -0.8873 b.

b = - 0.45696.

=> 2^ -0.45696 = 0.7285.

= 72.9%.

(b). T1= 45/7^ - 045696 = 109.5 hr.

V(TT)(17) = 109.5 {(17.51^ - 0.45696 – 0.51^ - 0.45696) / (1 - 0.45696)} .

V(TT) (17) = 109.5 {(4.7317 - 0.6863) / 0.54304} .

= 815.7 min .

= 13.595 hr.

8 0
3 years ago
Yan has already finished 3/5 of the 45 math problems he was assigned today. Each math problem took him 1 4/5 of a minute to comp
kobusy [5.1K]

Answer:

He will finish the rest of the problems in 32.4 minutes.

Step-by-step explanation:

Since we are given that Yan has completed 3/5 of 45 problems i.e.

\frac{3}{5}*45

27

Thus he has completed 27 problems

Remaining no. of problems are 45-27 = 18

Since he complete each problem in minutes = 1\frac{4}{5} =\frac{9}{5} =1.8

So, he completes 18 problems in minutes = 18 *1.8 = 32.4 minutes

Hence , He will finish the rest of the problems in 32.4 minutes.


3 0
3 years ago
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