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2 years ago

When you draw a multi-phase sample ____. Group of answer choices

Mathematics

1 answer:

notsponge [240]2 years ago

8 0

Answer:

The correct answer is letter "B": You use information from a first sample for collecting a subsequent subsample for further study.

Explanation:

Multi-phase sampling is a strategy by which a large number of data under study is taken, then a subsample of that pool is taken, and after that, another smaller subsample is taken in an attempt to count with samples that best might represent the whole population. Usually, the process takes collecting two different samples, but it can be applied as many times as necessary.

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Solve for k. k/7 + -31= -34

Ksju [112]

7
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k
k
7
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31
=
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34
7kk−31=−34

2
7
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I think that’s the right answer

7 0

2 years ago

a storage jug was 4/5 full of water when did get indicated 72 what was the full capacity of the storage jug

IRISSAK [1]

Answer:

90. ( was the full capacity of jug)

to solve this 

firstly let the full capacity of jug 

 

be. x

so, 

4/5*x = 72

x = 72*5/4

x = 90

hope it helps

6 0

2 years ago

1 Point

I am Lyosha [343]

Option C

The ratio for the volumes of two similar cylinders is 8 : 27

<h3>Solution:</h3>

Let there are two cylinder of heights "h" and "H"

Also radius to be "r" and "R"

$\text { Volume of a cylinder }=\pi r^{2} h$

Where π = 3.14 , r is the radius and h is the height

Now the ratio of their heights and radii is 2:3 .i.e

$\frac{\mathrm{r}}{R}=\frac{\mathrm{h}}{H}=\frac{2}{3}$

Ratio for the volumes of two cylinders

$\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\frac{\pi r^{2} h}{\pi R^{2} H}$

Cancelling the common terms, we get

$\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\left(\frac{\mathrm{r}}{R}\right)^{2} \times\left(\frac{\mathrm{h}}{\mathrm{H}}\right)$

Substituting we get,

$\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\left(\frac{2}{3}\right)^{2} \times\left(\frac{2}{3}\right)$

$\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\frac{2 \times 2 \times 2}{3 \times 3 \times 3}$

$\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\frac{8}{27}$

Hence, the ratio of volume of two cylinders is 8 : 27

7 0

2 years ago

8х + 5у = -7 — 7х + бу = — 4

Levart [38]

Answer: x = -0.2651 and y = -0.9759

Step-by-step explanation:

Solution by substitution method

8x+5y= -7

-7x+6y= -4 = 7x-6y=4

Suppose,

8x+5y=-7→(1)

7x-6y=4→(2)

Taking equation (1), we have

8x+5y= -7

⇒8x= -5y -7

⇒x= -5y-7 / 8 →(3)

Putting x= -5y-7 / 8

in equation (2), we get 7x-6y=4

7(-5y-7/8)-6y=4

⇒-35y-49-48y=32

⇒-83y-49=32

⇒-83y=32+49

⇒-83y=81

⇒y= 81 / -83

⇒y= -0.9759→(4)

Now, Putting y= -0.9759 in equation (3), we get

x= -5y-7

x= -5(-0.9759)-7/8

⇒x= 4.8795-7/8

⇒x= -2.1205/8

⇒x= -0.2651

∴x= -0.2651 and y = -0.9759

7 0

2 years ago

the length of a rectangle is equal to triple the width . if the perimeter is 8 centimeters .what is the length and the width of

madam [21]

Answer:

Length = 3 cm

Width = 1 cm

Step-by-step explanation:

Let the length of rectangle be l and width of rectangle be w.

According to problem,

l = 3w {Length of rectangle is equal to triple the width}

And Perimeter,P = 8 cm

Since, P = 2 ( l + w )

or 8 = 2( l + w)

Plug l =3w in the above perimeter equation.

We get:

8 = 2( 3w + w)

8 = 2(4w)

8 = 8w

or w = 1 cm

Then length ,l = 3w =3 * 1 = 3 cm

Hence length of rectangle is 3cm and width of rectangle is 1cm.

3 0

2 years ago