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Dafna1 [17]
3 years ago
15

Help with this question, please!! I don't understand!

Mathematics
1 answer:
kondor19780726 [428]3 years ago
3 0

Answer:

FE = 30°

Step-by-step explanation:

arc FGC = arc FG + arc GB + arc BC

220° = 90° + arc GB + 70° . . substitute known values

60° = arc GB . . . . . . . . . . . . . subtract 160°

__

External angle A is half the difference of arcs EG and GB:

30° = (1/2)(arc FE +90° -60°) . . . substitute known values

60° = arc FE + 30° . . . . . . . . . . . multiply by 2 and simplify

30° = arc FE . . . . . . subtract 30°

_____

The key to this problem is the relationship between external angle A and the measures of the arcs it subtends.

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Please help solve for x step by step ASAP!
ASHA 777 [7]

Answer:

x=26

Step-by-step explanation:

the angle is a right angle so

90-37= 53

53-1=51

52/2= 26 thats x?

if you dont understand i can still describe more

6 0
3 years ago
Which interval for the graphed function contains the local maximum? [–1, 0] [1, 2] [2, 3] [3, 4]
Ratling [72]

Answer:

Local maximum = [3, 4]

Step-by-step explanation:

Step 1: Plot the given points [–1, 0] [1, 2] [2, 3] [3, 4] and draw the graph.

Step 2: Observe the graph, it is a straight line. Which has local minimum and local maximum at the closed interval.

Here with I have attached the graph.

The graphed function at local maximum at [3, 4]

Thank you.

4 0
3 years ago
Read 2 more answers
−2(x + 3 − 4x) = 3x − 18<br><br> How many solutions for x does this equation have?
taurus [48]

Answer:

3

Step-by-step explanation:

because there are 3 x's

5 0
3 years ago
Jeb's weight w is 1/3rd of lago's weight a. Which equation could
Naddik [55]

Answer:

:w=1/3(a)

Step-by-step explanation:

w = 1/3 × a

If Lago is 150lb, Jeb's  =

1/3 x 150 = 50 lb

If Lago is 60lb, Jeb's  =

1/3 x 60 = 20lb

7 0
3 years ago
Which are the maximum values ? I will add a picture please help
Alik [6]

Answer:

58 at the point (9,8)

7 at the point (1, 1)

Step-by-step explanation:

The maximum points will be found in the vertices of the region.

Therefore the first step to solve the problem is to identify through the graph, the vertices of the figure.

The vertices found are:

(1, 10)

(1, 1)

(9, 5)

(9, 8)

We look for the values of x and y belonging to the region, which maximize the objective function f(x, y) = 2x + 5y. Therefore we look for the vertices with the values of x and y higher.

(1, 10), (9, 5), (9, 8)

Now we substitute these points in the objective function and select the one that produces the highest value for f (x, y)

f(1, 10) = 2(1) + 5(10) = 52\\\\f(9, 5) = 2(9) + 5(5) = 43\\\\f(9, 8) = 2(9) + 5(8) = 58

The point that maximizes the function is:

(9, 8) with f(9, 8) = 58

Then the value that produces the minimum of f(x, y) is (1, 1)

f(1, 1) = 2(1) + 5(1) = 7

5 0
3 years ago
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