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3 years ago

Pls if anyone can solve NOW

Mathematics

1 answer:

Yuki888 [10]3 years ago

3 0

Answer:

Step-by-step explanation:

For the graphing, we can graph both equations, and where they intercept is the answer. Okay, so we can give x random inputs and get y as an output which is one pair of coordinates. I usually like using 0 as x. y-3(0)=12. y-0=12. y=12. So for our first equation, on of the coordinates is (0,12). Now we can insert another input for x! ( I chose 1.) y-3(1)=12. y-3=12. y=15. So our other pair of coordinates for the first equation is (1,15). We can do the same with the second equation. 2y+8(0)= -4. 2y+0= -4. y=-2. The first pair of coordinates for the second equation is (0,-2). Another input we can put in is 1, again. 2y+8(1)=-4. 2y+8=-4. 2y= -12. y= -6. So our second pair of coordinates for our second equation is (1,-6). We can graph this with a graphing calculator, or mark these points and draw a straight line through them. When we draw a line through them, the part where the two lines intersect is the answer.

When we do substitution, we need to solve for x or y in the bottom equation. I want to solve for x. ( NOTE: IF YOU SOLVE FOR y, YOU STILL GET THE SAME ANSWER) x=-56-3y. Then we replace the x on the top equation with 56-3y. And we get: 2(56-3y)-y=0. We can use the distributive property. The answer I have is 112-6y-y=0. -6y-y is -7y. 112-7y=0. We can add 7y to both sides so they seperate the variables and the numbers. 112=7y. Lastly, divide by 7. For y, we get 16. To get x, we insert y, AKA 16 into x+3y= -56. x+3(16)=-56. x+48= -56. Our last step to get x is to subtract 48 from both sides leaving us with: x= -100. Our final answer is y= 16 and x= -100.

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ziro4ka [17]

Answer:

$\displaystyle x = \frac{\pi}{3} +k\, \pi$ or $\displaystyle x =- \frac{\pi}{3} +2\,k\, \pi$ , where $k$ is an integer.

There are three such angles between $0$ and $2\pi$ : $\displaystyle \frac{\pi}{3}$ , $\displaystyle \frac{2\, \pi}{3}$ , and $\displaystyle \frac{4\,\pi}{3}$ .

Step-by-step explanation:

By the double angle identity of sines:

$\sin(2\, x) = 2\, \sin x \cdot \cos x$ .

Rewrite the original equation with this identity:

$2\, (2\, \sin x \cdot \cos x) - 2\, \sin x + 2\sqrt{3}\, \cos x - \sqrt{3} = 0$ .

Note, that $2\, (2\, \sin x \cdot \cos x)$ and $(-2\, \sin x)$ share the common factor $(2\, \sin x)$ . On the other hand, $2\sqrt{3}\, \cos x$ and $(-\sqrt{3})$ share the common factor $\sqrt[3}$ . Combine these terms pairwise using the two common factors:

$(2\, \sin x) \cdot (2\, \cos x - 1) + \left(\sqrt{3}\right)\, (2\, \cos x - 1) = 0$ .

Note the new common factor $(2\, \cos x - 1)$ . Therefore:

$\left(2\, \sin x + \sqrt{3}\right) \cdot (2\, \cos x - 1) = 0$ .

This equation holds as long as either $\left(2\, \sin x + \sqrt{3}\right)$ or $(2\, \cos x - 1)$ is zero. Let $k$ be an integer. Accordingly:

$\displaystyle \sin x = -\frac{\sqrt{3}}{2}$ , which corresponds to $\displaystyle x = -\frac{\pi}{3} + 2\, k\, \pi$ and $\displaystyle x = -\frac{2\, \pi}{3} + 2\, k\, \pi$ .
$\displaystyle \cos x = \frac{1}{2}$ , which corresponds to $\displaystyle x = \frac{\pi}{3} + 2\, k \, \pi$ and $\displaystyle x = -\frac{\pi}{3} + 2\, k \, \pi$ .

Any $x$ that fits into at least one of these patterns will satisfy the equation. These pattern can be further combined:

$\displaystyle x = \frac{\pi}{3} + k \, \pi$ (from $\displaystyle x = -\frac{2\,\pi}{3} + 2\, k\, \pi$ and $\displaystyle x = \frac{\pi}{3} + 2\, k \, \pi$ , combined,) as well as
$\displaystyle x =- \frac{\pi}{3} +2\,k\, \pi$ .

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c. Unclear question (isn't it the same as b.?)

Step-by-step explanation:

The data below is what I've worked according to, which isn't very clear from the question so the answers are only correct if this is the correct table of data;

$\left[\begin{array}{ccc}&No \ Sports&Sports\\Female&10&32\\Male&7&21\end {array}\right]$

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