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2 years ago

I will give brainliest. What is the hypotenuse and how do I get it?

Mathematics

1 answer:

Ivan2 years ago

4 0

Step-by-step explanation:

by Pythagoras theorem:

perpendicular² + base²= hypotenuse²

(1/√2)²+ (1/√3)² = H²

1/2+1/3= H²

5/6 = H²

√(5/6 )= H

√5/√6 = H

plz mark my answer as brainlist plzzzz.

hope this will be helpful to you

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2 years ago

A country's population in 1995 was 32 million. In 1997 it was 34 million. Estimate the population in 2003 using the exponential

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2 years ago

What is the simplified form of the following expression? 2 startroot 18 endroot 3 startroot 2 endroot startroot 162 endroot

nataly862011 [7]

The simplified form of the provided expression of 2 startroot 18 endroot +3 startroot 2 endroot startroot +162 endroot is 18√2.

<h3>What is the simplified form of an equation?</h3>

The simplified form of an equation is the simplest way of expressing the equation, by applying the required operations of mathematics.

The equation provided in the problem is,

$2\sqrt{18}+3\sqrt{2}+\sqrt{162}$

Let the simplified form of the above expression is <em>n. </em>Thus,

$n=2\sqrt{18}+3\sqrt{2}+\sqrt{162}$

Rewrite the equation to solve it further as,

$n=2\sqrt{3\times3\times2}+3\sqrt{2}+\sqrt{9\times9\times2}\\n=2\sqrt{3^2\times2}+3\sqrt{2}+\sqrt{9^2\times2}$

The square of the term cancel out the square root of it. Thus,

$n=2\times3\sqrt{2}+3\sqrt{2}+9\sqrt{2}\\n=6\sqrt{2}+3\sqrt{2}+9\sqrt{2}\\n=(6+3+9)\sqrt{2}\\n=18\sqrt{2}$

Thus, the simplified form of the provided expression of 2 startroot 18 endroot +3 startroot 2 endroot startroot +162 endroot is 18√2.

Learn more about the simplified form here;

brainly.com/question/1597694

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1 year ago