Answer:
![f_X(k)=\binom{4}{k}0.003^k0.997^{4-k}](https://tex.z-dn.net/?f=f_X%28k%29%3D%5Cbinom%7B4%7D%7Bk%7D0.003%5Ek0.997%5E%7B4-k%7D)
Step-by-step explanation:
Recall that a <em>probability mass function</em> defined on a discrete random variable X is just a function that gives the probability that the random variable equals a certain value k
In this case we have the event
“The computer will ask for a roll to the left when a roll to the right is appropriate” with a probability of 0.003.
Then we have 2 possible events, either the computer is right or not.
Since we have 4 computers in parallel, the situation could be modeled with a binomial distribution and the probability mass function
This gives the probability that k computers are wrong at the same time.
This is very similar to the last question:-
0.51No = No e^_0.0001t
t = ln 0.51 / 0.0001
= 6733 years
Answer:
7.8 x 10^4 or 7.8e4 hope this helps!