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3 years ago

(b) factorise (3m-1)(6-a)-(m+3)(6-a)

Mathematics

1 answer:

Step2247 [10]3 years ago

7 0

Answer:

Step-by-step explanation:

(3m-1)(6-a)-(m+3)(6-a)

=3m(6-a)-1(6-a)-m(6-a)+3(6-a)

=18m-3ma-6+a-6m+ma+18-3a

=12m-2ma+12-2a

=2(6m-ma+6-a)

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The formula T= 2pi sqrt(L/32) relates the time, T, in seconds for a pendulum with the length, L, in feet, to make one full swing

tester [92]

The length of pendulum is 2.485 feet

<h3><u><em>Solution:</em></u></h3>

Given that,

The formula T= 2pi sqrt(L/32) relates the time, T, in seconds for a pendulum with the length, L, in feet, to make one full swing back and forth

<u><em>Therefore, the given formula is:</em></u>

$T=2\pi \sqrt{\frac{L}{32} }$

We have to find the length of pendulum that makes one full swing in 1.75 seconds

So the modify the given equation to find "L"

$T=2\pi \sqrt{\frac{L}{32} }\\\\ \sqrt{\frac{L}{32} }=\frac{T}{2 \pi}\\\\\text{Taking square root on both sides }\\\\\frac{L}{32} = \frac{T^2}{4 \pi^2}\\\\L = \frac{T^2}{4 \pi^2} \times 32\\\\L = \frac{T^2}{\pi^2 } \times 8$

Substitute T = 1.75 seconds and $\pi = 3.14$

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4 years ago

(b) factorise (3m-1)(6-a)-(m+3)(6-a)​

(b) factorise (3m-1)(6-a)-(m+3)(6-a)