(-1-3i)(-6-i)
=6+i+18i+3i^2
=3i^2+19i+6. Hope it help!
Step-by-step explanation:
(1) Factor the GCF out of the trinomial on the left side of the equation. (2 points: 1 for the GCF, 1 for the trinomial) 2x²+6x-20=0
2x²+6x-20
2(x²+3x-10)
the factors are 2 and (x²+3x-10)
(2) Factor the polynomial completely. (4 points: 2 point for each factor)
2(x²+3x-10)
2(x²-2x+5x-10)
2(x(x-2) + 5(x-2)) group like terms
2(x+5)(x-2)
(3) If a product is equal to zero, we know at least one of the factors must be zero. And the constant factor cannot be zero. So set each binomial factor equal to 0 and solve for x, the width of your project. (2 points: 1 point for each factor)
constant = 2 cannot be zero
the other factors are (x+5) and (x-2)
(x+5)=0 => x= -5
or
(x-2)=0 => x=2
(4) What are the dimensions of your project? Remember that the width of your project is represented by x. (2 points: 1 point for each dimension)
thank you so much, sorry if it's a little confusing!!
(it is indeed confusing, because physical dimensions cannot be negative)
The dimensions of the project (assumed a rectangle) are +2 and -5
I belive the answer would be....
49.5-37.5=12
2•12=24
![[n][n+8]=0](https://tex.z-dn.net/?f=%5Bn%5D%5Bn%2B8%5D%3D0)
if either or both of
![[n]](https://tex.z-dn.net/?f=%5Bn%5D)
and
![[n+8]](https://tex.z-dn.net/?f=%5Bn%2B8%5D)
are 0, i.e. if one or both of

and

are even. But both will be even if

is even, and odd otherwise, so any even

will be a solution, e.g.

.
First set change the function f(x) to y so
that it would be

Then set y = 0

Then solve for x
X = - 3
To graph it, just plot the point (-3,0) on the x-axis