Given:
The function is
![f(x)=\dfrac{8\sqrt[3]{x}-8}{9}](https://tex.z-dn.net/?f=f%28x%29%3D%5Cdfrac%7B8%5Csqrt%5B3%5D%7Bx%7D-8%7D%7B9%7D)
To find:
The inverse function
.
Solution:
We have,
![f(x)=\dfrac{8\sqrt[3]{x}-8}{9}](https://tex.z-dn.net/?f=f%28x%29%3D%5Cdfrac%7B8%5Csqrt%5B3%5D%7Bx%7D-8%7D%7B9%7D)
Step 1: Putting f(x)=y, we get
![y=\dfrac{8\sqrt[3]{x}-8}{9}](https://tex.z-dn.net/?f=y%3D%5Cdfrac%7B8%5Csqrt%5B3%5D%7Bx%7D-8%7D%7B9%7D)
Step 2: Interchange x and y.
![x=\dfrac{8\sqrt[3]{y}-8}{9}](https://tex.z-dn.net/?f=x%3D%5Cdfrac%7B8%5Csqrt%5B3%5D%7By%7D-8%7D%7B9%7D)
Step 3: Isolate variable y.
![9x=8\sqrt[3]{y}-8](https://tex.z-dn.net/?f=9x%3D8%5Csqrt%5B3%5D%7By%7D-8)
![9x+8=8\sqrt[3]{y}](https://tex.z-dn.net/?f=9x%2B8%3D8%5Csqrt%5B3%5D%7By%7D)
![\dfrac{9x+8}{8}=\sqrt[3]{y}](https://tex.z-dn.net/?f=%5Cdfrac%7B9x%2B8%7D%7B8%7D%3D%5Csqrt%5B3%5D%7By%7D)
Taking cube on both sides, we get


Step 4: Putting
, we get

Therefore, the correct option is C.
Transpose the equation:
8x+6y=30
First minus 8x from each side of the equation.
6y=30-8x
Then divide each side by 6.
y=5-1.33x or if you want the answer in exact form:
y=5-4/3x
The slope is 4/3 or 1.333.
Answer:
Step-by-step explanation:
KL = JK, so ΔJKL is an isocesles triangle, then m∠J = m∠L
KL is a tangent line, so ∠JKL = 90°,
so m∠J = 45°
That would be 1
I hope I've helped!
Answer:
3.89
Step-by-step explanation:
5.42+2.25=7.67
7.67-3.78=3.89
Hope this helps