Algebra help please?
1 answer:
Answer is 3 seconds
When the bullet reaches the ground, ground being x in graph (and here its s which is = 0)
s = -16t^2 + 48t
s = 0, solve for t
0 = -16t^2 + 48t
0 = t ( -16t + 48)
0 = 16t ( - t + 3)
now you have two equation
0 = 16t and 0 = -t +3 ( you can look at the graph line touches x twice)
0 = 16 t
0 = t ( you know its false, because time = 0)
You are left with
0 = -t + 3
t = 3
It takes 3 seconds for the bullet to return to the ground.
// Hope this helps.
You might be interested in
Answer:
Step-by-step explanation:
Given:
To solve this equation, we need to isolate on one side of the equation algebraically. I see that we have like terms, but they are on opposite sides of the equal sign. Let's add
to both sides.
To isolate x, divide both sides by 7.