Ask question

Ask question

All categories

2 years ago

11

An apartment has 1026 square feet of carpeting. How much is this in square meters? Use the following conversion: 1 square meter

is 10.8 square feet.

1 answer:

kotegsom [21]2 years ago

8 0

The answer to the question would be 95 square meters

You might be interested in

The linear functions f(x) and g(x) are represented on the graph, where g(x) is a transformation of f(x):

Brilliant_brown [7]

Answer:

Part A: Determine the test average for your math class after completing test 2. (2 points)

Part B: Determine the test average for your science class after the completing test 2. (2 points)

Part C: Which class had a higher average after completing test 4? Show work to support your answer. (6 points)

I am finding itz answer, pls help

7 0

2 years ago

What adds to 60 and multiples to 900

notsponge [240]

Answer:

30

Step-by-step explanation:

30 + 30 = 60

3* 3 = 9

Add the 0s

30 * 30 = 900

I hope I helped!

Let me know if you need anything else!

~ Zoe

4 0

2 years ago

Read 2 more answers

) Set up a double integral for calculating the flux of F=3xi+yj+zk through the part of the surface z=−5x−2y+2 above the triangle

Fynjy0 [20]

The surface (call it $S$ ) is a triangle with vertices at the points

$x=0,y=0\implies z=2\implies(0,0,2)$

$x=0,y=2\implies z=-2\implies(0,2,-2)$

$x=2,y=0\implies z=-8\implies(2,0,-8)$

Parameterize $S$ by

$\vec s(u,v)=(1-v)(2,0,-8)+v\bigg((1-u)(0,2,-2)+u(0,0,2)\bigg)=(2-2v,2v-2uv,-8+6v+4uv)$

with $0\le u\le1$ and $0\le v\le1$ . Take the normal vector to $S$ to be

$\vec s_v\times\vec s_u=(20v,8v,4v)$

Then the flux of $\vec F$ across $S$ is

$\displaystyle\iint_S\vec F(x,y,z)\cdot\mathrm d\vec S=\int_0^1\int_0^1\vec F(x(u,v),y(u,v),z(u,v))\cdot(\vec s_v\times\vec s_u)\,\mathrm du\,\mathrm dv$

$=\displaystyle\int_0^1\int_0^1(6-6v,2v-2uv,-8+6v+4uv)\cdot(20v,8v,4v)\,\mathrm du\,\mathrm dv$

$=\displaystyle8\int_0^1\int_0^1(11v-10v^2)\,\mathrm du\,\mathrm dv=\boxed{\frac{52}3}$

8 0

3 years ago

Does Anyone have idea how to solve this problem?

garik1379 [7]

A.

5 * 2 = 10

8 * 2 = 16

10 cm by 16 cm is the new dimensions. Area = 160 sq cm. Perimeter = 52 cm.

B.

5 * 3 = 15

8 * 3 = 24

15 cm by 24 cm is the new dimensions. Area = 360 sq cm. Perimeter = 78 cm.

C.

The areas for the different sized photos both still maintain a ratio of 5:8 cm.

6 0

2 years ago

Read 2 more answers

25. The temperature was -7°F. During the

Alja [10]

Answer:

13

Step-by-step explanation:

6-(-7)=13

4 0

2 years ago