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Ghella [55]
2 years ago
6

Find the inverse function of y=9x

Mathematics
1 answer:
zloy xaker [14]2 years ago
4 0

Answer:

Replace  

F

(

x

)

with  

y

.

y

=

9

x

Interchange the variables.

x

=

9

y

Solve for  

y

.

Tap for more steps...

y

=

x

9

Solve for  

y

and replace with  

F

−

1

(

x

)

.

Tap for more steps...

F

−

1

(

x

)

=

x

9

Step-by-step explanation:

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Example of Order of operations
uysha [10]
6/2(1+2)
= 6/2(3)
= 6/6
= 1
3 0
2 years ago
Median math question
Feliz [49]

Answer:

27

Step-by-step explanation:

25,16,21,30

Put the numbers in order from smallest to largest

16,21,25,30

The median is the middle and the median is 25  so the new number must be 25 or larger

The only number on the the list that is 25 or largest is 27

8 0
3 years ago
If 3* = 1 What will be the value of x?​
zvonat [6]

Answer:

X=0

Step-by-step explanation:

It is a law that

{a}^{0}  = 1 \:  \:  \:  \:

Number( a) shouldn't be zero.

5 0
2 years ago
A researcher compares the effectiveness of two different instructional methods for teaching electronics. A sample of 138 student
yan [13]

Answer:

The 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for the difference between population means is:

CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}

The information provided is as follows:

n_{1}= 138\\n_{2}=156\\\bar x_{1}=61\\\bar x_{2}=64.6\\\sigma_{1}=18.53\\\sigma_{2}=13.43

The critical value of <em>z</em> for 98% confidence level is,

z_{\alpha/2}=z_{0.02/2}=2.326

Compute the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 as follows:

CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}

     =(61-64.6)\pm 2.326\times\sqrt{\frac{(18.53)^{2}}{138}+\frac{(13.43)^{2}}{156}}\\\\=-3.6\pm 4.4404\\\\=(-8.0404, 0.8404)\\\\\approx (-8.04, 0.84)

Thus, the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

5 0
3 years ago
The frequency distribution chart below represents scores from a math quiz.
Inessa05 [86]

The frequency distribution chart of the math quiz has a data that is skewed left.

<h3>How to interpret the shape of the histogram?</h3>

From the complete question (see attachment for histogram), we have the following highlight:

The dataset on the right-hand side is taller than those on the left.

This means that the dataset is skewed left.

Hence, the statement that best describes the data is (a) The data is skewed left.

Read more about skewness at:

brainly.com/question/27701525

#SPJ1

8 0
2 years ago
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