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2 years ago

Find the inverse function of y=9x

Mathematics

1 answer:

zloy xaker [14]2 years ago

4 0

Answer:

Replace

(

)

with

Interchange the variables.

Solve for

Tap for more steps...

Solve for

and replace with

−

(

)

Tap for more steps...

−

(

)

Step-by-step explanation:

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Example of Order of operations

uysha [10]

6/2(1+2)
= 6/2(3)
= 6/6
= 1

3 0

2 years ago

Median math question

Feliz [49]

Answer:

Step-by-step explanation:

25,16,21,30

Put the numbers in order from smallest to largest

16,21,25,30

The median is the middle and the median is 25 so the new number must be 25 or larger

The only number on the the list that is 25 or largest is 27

8 0

3 years ago

If 3* = 1 What will be the value of x?

zvonat [6]

Answer:

X=0

Step-by-step explanation:

It is a law that

${a}^{0} = 1 \: \: \: \:$

Number( a) shouldn't be zero.

5 0

2 years ago

A researcher compares the effectiveness of two different instructional methods for teaching electronics. A sample of 138 student

yan [13]

Answer:

The 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for the difference between population means is:

$CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$

The information provided is as follows:

$n_{1}= 138\\n_{2}=156\\\bar x_{1}=61\\\bar x_{2}=64.6\\\sigma_{1}=18.53\\\sigma_{2}=13.43$

The critical value of <em>z</em> for 98% confidence level is,

$z_{\alpha/2}=z_{0.02/2}=2.326$

Compute the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 as follows:

$CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$

$=(61-64.6)\pm 2.326\times\sqrt{\frac{(18.53)^{2}}{138}+\frac{(13.43)^{2}}{156}}\\\\=-3.6\pm 4.4404\\\\=(-8.0404, 0.8404)\\\\\approx (-8.04, 0.84)$

Thus, the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

5 0

3 years ago

The frequency distribution chart below represents scores from a math quiz.

Inessa05 [86]

The frequency distribution chart of the math quiz has a data that is skewed left.

<h3>How to interpret the shape of the histogram?</h3>

From the complete question (see attachment for histogram), we have the following highlight:

The dataset on the right-hand side is taller than those on the left.

This means that the dataset is skewed left.

Hence, the statement that best describes the data is (a) The data is skewed left.