To solve for the time an object takes to hit the ground, the equation
<em>y</em> <em>= y₀ + v₀t + ½gt²</em>, or just <em>0 = y₀ +½gt²</em> since there is no initial velocity and the final y position is 0 (since it is on the ground). Therefore, <em>t = (−2y₀/g)^½.</em>
(-2*60/-9.8)^½ = 3.50 seconds.
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Answer:
∠ PQR = 70°
Step-by-step explanation:
The tangent- tangent angle PQR is half the difference of the intercepted arcs.
minor arc PR = 360° - 250° = 110°
Then
∠ PQR =
(250 - 110)° =
× 140° = 70°
Answer:
c. how late it is in the evening is a function of the length of time the shutter needs to stay open.
Answer:
see explanation
Step-by-step explanation:
(a)
0 < 5 ⇒ f(0) = x + 4 = 0 + 4 = 4
f(0) = 4
(b)
5 ≤ 6 < 7 ⇒ f(6) = 8
Answer:
- The solution is (x, y) = (-2, 0)
- A graph is attached
Step-by-step explanation:
The graph shows the solution. The first equation has a y-intercept of -4 and a slope of -2, so will go through the point (-2, 0).
The second equation has a y-intercept of +4 and a slope of 2, so will go through the point (-2, 0).
Both equations have the same x-intercept, so that x-intercept is the solution to the system of equations.