Answer:
Formula
Step-by-step explanation:
Answer:
Step-by-step explanation:
<em>Let P(W) represents the probability that Paul wins</em>
<em>Let P(W') represents the probability that Paul does not win</em>
Given
Required
In probability, the sum of opposite probability equals 1;
This implies that
Substitute in the above equation
becomes
Subtract 
from both sides
Solve fraction (start by taking the LCM)
Hence, the probability that Paul doesn't win is
In order to find out where your holes and asymptotes are is to factor both the top and the bottom of that rational function. The numerator factors to (x+2)(x-2) and the denominator factors to x(x+1)(x-2). So since there is an (x-2) in both the numerator and denominator, that is called a removable discontinuity which we also know as a hole. The other factors in the denominator, the x and the (x+1) are vertical asymptotes, or values of x that make the rational function undefined (you're NEVER allowed to have a 0 in the denominator of a fraction!). So your correct choice is c. The way you find the y coordinate for the hole is to plug in 2 for x and solve it for y. No biggie.
<u><em>Answer:</em></u>
1)
f(x)→ ∞ when x→∞ or x→ -∞.
2)
when x→ ∞ then f(x)→ -∞
and when x→ -∞ then f(x)→ ∞
<u><em>Step-by-step explanation:</em></u>
<em>" The </em><em>end behavior</em><em> of a polynomial function is the behavior of the graph of as approaches positive infinity or negative infinity. The degree and the leading coefficient of a polynomial function determine the end behavior of the graph "</em>
1)
a 14th degree polynomial with a positive leading coefficient.
Let f(x) be the polynomial function.
Since the degree is an even number and also the leading coefficient is positive so when we put negative or positive infinity to the function i.e. we put x→∞ or x→ -∞ ; it will always lead the function to positive infinity
i.e. f(x)→ ∞ when x→∞ or x→ -∞.
2)
a 9th degree polynomial with a negative leading coefficient.
As the degree of the polynomial is odd and also the leading coefficient is negative.
Hence when x→ ∞ then f(x)→ -∞ since the odd power of x will take it to positive infinity but the negative sign of the leading coefficient will take it to negative infinity.
When x→ -∞ then f(x)→ ∞; since the odd power of x will take it to negative infinity but the negative sign of the leading coefficient will take it to positive infinity.
Hence, when x→ ∞ then f(x)→ -∞
and when x→ -∞ then f(x)→ ∞
Answer:
let the third side be x
Using pythagoras theorem we get,
(58)^2 = (42)^2 + (x)^2
3364=1764+x^2
x^2=3364-1764
x^2= 1600
x=√(1,600)
x=40
