Question

What are the coordinates of J'?

Answer 1

Answer:

$F'(-\frac{10}{3},-\frac{8}{3})$

or

$F'(-3.33,-2.67)$

Step-by-step explanation:

we know that

The coordinates of point F are (-5,-4) (see the figure)

In this problem

A dilation with a scale factor 2/3 about the origin is described using the following notation:

$(x,y) ----> (\frac{2}{3}x,\frac{2}{3}y)$

so

Applying the rule of the dilation to point F

$F(-5,-4) ----> F'(\frac{2}{3}(-5),\frac{2}{3}(-4))$

$F(-5,-4) ----> F'(-\frac{10}{3},-\frac{8}{3})$

$F(-5,-4) ----> F'(-3.33,-2.67)$