Where in the bible is there an indication of the value of pi what was the approximate value?

1 answer:

7 0

The Bible, a book that is considered the perfect word of a perfect god tells us what the value of Pi is. Let's see verse 1 Kings 7:23
He also melted a sea of ten cubits from one side to the other, perfectly round; Its height was five cubits, and a cord of thirty cubits encircled it.

These are a list of specifications for the great temple of King Solomon, built about 950 BCE, and his interest here is that it gives a value of π = 3. If we divide 30 cubits between 10 cubits (which are the measures mentioned in written radical) gives us exactly 3.

We know that the length of the circumference is calculated l = 2 · π · r; Since 2 · r is the diameter, it can also be said that

circumference = diameter × π

If we go back to what the Bible says, the diameter is 5 meters and the circumference of 15:

circumference = diameter × π -> 15 = 5 × π

with which the value of π is 3.

This calculation of Pi is a bad approximation to the real value. The figure of 3 in the Bible compared with the real one which is 3.1416 ... indicates an error of about 6%.

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√6 x √27 is equal to

solong [7]

Answer:

$9\sqrt{2} = 12.727922061$

7 0

3 years ago

Help me with this problem please right away

svlad2 [7]

Answer:

$6\frac{1}{2} = A$

Step-by-step explanation:

The first step is to use the Distance Formula to figure out the lengths of the two legs:

$\sqrt{[-x_1 + x_2]^{2} + [-y_1 + y_2]^{2}} = D$

R(1, 1) and P(−1, −2) ↷

$\sqrt{[1 + 1]^{2} + [2 + 1]^{2}} = \sqrt{2^{2} + 3^{2}} = \sqrt{4 + 9} = \sqrt{13}\\ \\ \sqrt{13} = RP$

Q(2, −4) and P(−1, −2) ↷

$\sqrt{[1 + 2]^{2} + [2 - 4]^{2}} = \sqrt{[-2]^{2} + 3^{2}} = \sqrt{4 + 9} = \sqrt{13} \\ \\ \sqrt{13} = QP$

* So, by my calculations, we have an isosceles right triangle, and according to the 45°-45°-90° triangle theorem, we automatically know that the hypotenuse, RQ, is $\sqrt{26}$ :

30°-60°-90° triangle theorem

2x, x, x√3

↑ ↑ ↑

h leg leg

45°-45°-90° triangle theorem

x√2, x, x

↑ ↑ ↑

h legs

So now, we have to find the area of the triangle by taking half of either height or base, then multiplying that by the height or base, but since this is an isosceles right triangle, it does not matter:

$[\frac{h}{2}][b] = A \: \:OR\: \: [\frac{b}{2}][h] = A \: \:OR \: \: \frac{hb}{2} = A$