<span>(a) How fast is it moving when it reaches 12.0 m?
To determine the velocity as it reaches 12.0 m, we use one of the kinematic equations,
</span>V^2 = Vo^2 + 2gh
<span>where Vo = 20 m/s. </span>
<span> g = -9.8 m/s^2 </span>
<span> h = 12.0 m. </span>
V^2 = 20^2 + 2(-9.8)(12.0)
<span>V^2 = 164.8
V = 12.84 m/s
(b) How long is required to reach this height?
To determine the maximum height, we use the same equation we used above,
</span>V^2 = Vo^2 + 2gh
where Vo = 20 m/s.
g = -9.8 m/s^2
V = 0 (since at the maximum height velocity is zero)
0^2 = 20^2 + 2(-9.8)h
<span>h = 20.41 m
(c) Why are there two answers for (b)?
There are two answers for b because it would travel a distance up and travel a distance down.</span>
Answer:
the bottle would stay in its squashed shape, and it will only regain its shape if u remove the cork
Explanation:
because theres not enough air inside to let the bottle to go back its normal form. Its like when u let the air out of a balloon, theres no air inside to let it stay in its 'big or expanded' form.
Answer: A) Forces of attraction and repulsion exist between gas particles at close range.
Explanation:
The <u>Ideal Gas equation</u> is:
Where:
is the pressure of the gas
is the volume of the gas
the number of moles of gas
is the gas constant
is the absolute temperature of the gas in Kelvin
According to this law, molecules in gaseous state do not exert any force among them (attraction or repulsion) and the volume of these molecules is small, therefore negligible in comparison with the volume of the container that contains them. In this sense, real gases can behave approximately to an ideal gas, under conditions of high temperature and low pressures.
However, at low temperatures or high pressures, real gases deviate significantly from ideal gas behavior. This is because at low temperatures molecules begin to move slower, allowing the repulsive and attractive forces among them to take effect. In fact, <u>the attraction forces are responsible for the condensation of the gas</u>. In addition, at high pressures the volume of molecules cannot be approximated to zero, hence the volume of these molecules is not negligible anymore.
90 degrees - 30 = 60 degrees
Velocity = (5m/s - 4.35m/s x cos(30)) / cos(60)
Velocity = 2.47 m/s
The answer is D) 2.47 m/s at 61.9 degrees
