Answer:
1) Determine the domain of the following functions: d ... 3) If g(x) = x + 3 and f(x)= x² – 2x, find the value of f(g(a)). ... 6) Given the graph of f(x) to the right, determine: ... 8) Given f(x)= x? and g(x)= 2* The inverse of g is a function, but the inverse off is ... -3(x-1)= -5 4 (-3). -3x+ 3 = y. 10) The graph of a function f (x) is given at the.
Explanation:
Answer:
When the source of pollution is widely distributive in nature, it is called as the Non-point source pollution, for example, <em>acid rain</em>.
Explanation:
the source of pollution when is <em>not concentrated over a particular area</em> or any particular defined pinpoint is termed to be as the Non - point source pollution.
this type of pollution is very hard to be monitored or controlled due to its nature of widely distributive nature of the origin. It has <em>several pathways</em> for the effect to undertake and thus the control over the effect is <em>not easily accessible. </em>
For example, during rain, the tree fall off can enter water stream from any source, either be it open lake or ponds or even street fall offs.
⁻Answer:
Ne=1.8 *10^37
Explanation:
Current density J=Iₐ /(πr²)
= 8/(π* (1.5*10⁻³/2)²)= 4.53*10⁶ A/m²
Drift velocity = J/ne =4.53*10⁶ /(8.5×1028 *1.6×10−19 ) = 3.33 ×10−4 m/s
volume = πr²h= π * (1.5*10⁻³/2)² * 3 = 5.3 ×10−6 m³
Ne=1.8 *10^37
Answer:
Ns = 293 turns
Explanation:
The magnetic field of a solenoid is given as follows:
B = μ₀NI/L
where,
B = Magnetic Field = (40.5 Gauss)(1 T/10000 Gauss) = 4.05 x 10⁻³ T
μ₀ = Permeability of Free Space = 4π x 10⁻⁷ T/Am
N = No. turns in solenoid = ?
I = Current = 0.05 A
L = Length = 10 cm = 0.1 m
Therefore,
4.05 x 10⁻³ = (4π x 10⁻⁷ )(N)(0.05)/0.1
N = (4.05 x 10⁻³)/(6.28 x 10⁻⁷)
N = 6446 turns
Now, we use turns ratio formula for transformer:
Np/Ns = Vp/Vs
where,
Np = No. of turns in primary coil = 6446 turns
Ns = No. of turns in secondary coil = ?
Vp = Primary Voltage = 220 V
Vs = Secondary Voltage = 10 V
Therefore,
6446 turns/Ns = 220 V/10 V
Ns = 64460 turns/220 V
<u>Ns = 293 turns</u>
Answer:
W=315 x 10⁵ J
Explanation:
Given that
F= 2.5 x 10⁵ N
d= 90 m
K.E.=5.4 x 10⁷ J
We know that work done by all force is equal to the change in kinetic energy
Lets take work done by catapult is W
W + F.d= K.E.
W= 5.4 x 10⁷ - 2.5 x 10⁵ x 90 J
W= (540 - 25 x 9) 10⁵ J
W=315 x 10⁵ J