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3 years ago

14

A wind generator, such as the one shown , uses the power of wind to generate electricity What do you think is happening inside t

he wind generator to convert the energy of the spinning blades into electricity? Make your best guess.

1 answer:

chubhunter [2.5K]3 years ago

5 0

Answer:

The wind spins blades of a wind turbine around a rotor, which spins a generator, which creates electricity (a generator converts mechanical energy into electricity).

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Which would melt first, germanium with a melting point of 1210 k or gold with a melting point of 1064oc?

iren2701 [21]

<span>Germanium To determine which melts first, convert their melting temperatures so they're both expressed on same scale. It doesn't matter what scale you use, Kelvin, Celsius, of Fahrenheit. Just as long as it's the same scale for everything. Since we already have one substance expressed in Kelvin and since it's easy to convert from Celsius to Kelvin, I'll use Kelvin. So convert the melting point from Celsius to Kelvin for Gold by adding 273.15 1064 + 273.15 = 1337.15 K So Germanium melts at 1210K and Gold melts at 1337.15K. Germanium has the lower melting point, so it melts first.</span>

8 0

3 years ago

During the time a compact disc (CD) accelerates from rest to a constant rotational speed of 477 rev/min, it rotates through an a

atroni [7]

Answer:

<em>126.01 rad/s^2</em>

<em></em>

Explanation:

since it starts from rest, initial angular speed ω' = 0 rad/s

angular speed N = 477 rev/min

angular speed in rad/s ω = $\frac{2\pi N}{60}$ = $\frac{2*3.142* 477}{60}$ = 49.95 rad/s

angular displacement ∅ = 1.5758 rev

angular displacement in rad/s = $2\pi N$ = 2 x 3.142 x 1.5758 = 9.9 rad

angular acceleration $\alpha$ = ?

using the equation of angular motion

ω^2 = ω'^2 + 2 $\alpha$ ∅

imputing values, we have

$49.95^{2} = 0^{2} + (2 *\alpha*9.9 )$

2495 = 19.8 $\alpha$

$\alpha$ = 2495/19.8 = <em>126.01 rad/s^2</em>

8 0

3 years ago

If a nucleus was as big as a nonpareil, an atom would be ____

Mamont248 [21]

Answer:

small marble

Explanation:

A nonpareil are confectionery tiny ball items that are made up of starch and sugar. It is very small of the size of sugar crystal or sand grains. They were the miniature version of the comfits. They are generally opaque white but bow available in all colors.

In the context, if the nucleus is compared to the size of a nonpareil then its atom would be of the size of small size marble. An atom is bigger in size than that of nucleus as the nucleus is located inside the atoms.

6 0

3 years ago

Abox has a mass of 14.4 kg. The length is 4 m longthe width is 1 m and the height is 5 m. What is the density of the box?

valkas [14]

Answer:

0.72 kg per cubic m

Explanation:

Mass = 14.4 kg

Volume = lbh = 4*1*5 = 20 cubic m

$\because \: density \\ \\ = \frac{mass}{volume} \\ \\ = \frac{14.4}{20} \\ \\ = 0.72 \: kg {m}^{ - 3}$

3 0

3 years ago

A wildlife photographer uses a moderate telephoto lens of focal length 135 mm and maximum aperture f/4.00 to photograph a bear t

labwork [276]

Answer:

<h3>(A) The width $x = 0.24 \times 10^{-3}$ m</h3><h3>(B) The new width is $1.32 \times 10^{-3}$ m</h3>

Explanation:

Given :

Focal length $f = 135 \times 10^{-3} m$

Maximum aperture $D = \frac{f}{4}$

Wavelength $\lambda = 550 \times 10^{-9}$ m

(A)

From rayleigh criterion,

$\theta = \frac{1.22 \lambda }{D}$

$\theta =\frac{ 1.22 \times 550 \times 10^{-9} }{33.75 \times 10^{-3} }$

$\theta = 1.98 \times 10^{-5}$ rad

From angle formula,

$x = R\theta$

Where $R =$ 12 m ( given in example )

$x = 12 \times 1.98 \times 10^{-5}$ m

$x = 23.76 \times 10^{-5}$

$x = 0.24 \times 10^{-3}$ m

(B)

We know that $\theta$ is proportional to the $x$ and inversely proportional to the $D$

so we write the new width, here $x$ is 5.5 times larger than above case

$x = 0.24 \times 10^{-3} \times \frac{22}{4}$

$x = 1.32 \times 10^{-3}$ m

6 0

3 years ago