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Fudgin [204]
3 years ago
11

What is the probability of drawing yellow marble followed by a red marble from a bag containing 12 yellow marbles, 14 red marble

s, and 15 green marbles if the first marble is not replaced?
Mathematics
2 answers:
Xelga [282]3 years ago
4 0

Answer:

21/205

Step-by-step explanation:

Bag contains 12 yellow marbles, 14 red marbles, and 15 green marbles.

Total marbles=12+14+15

                      = 41

P(drawing a yellow marble)

=number of yellow marbles/total number of marbles

= 12/41

P(drawing a red marble after the yellow one without replacing it)

= number of red marbles left/number of total marbles left

= 14/40

P(drawing yellow marble followed by a red marble without replacement)

= \dfrac{12}{41}\times \dfrac{14}{40}

=21/205

Evgen [1.6K]3 years ago
3 0
The probability of drawing both without replacing either is :

14/41 * 12/40 = 7/41 * 3/5 = 21/205

The probability of drawing both WITH replacement is:
14/41 * 12/41 = 168/ 1681

there you have it :D
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