The slopes of two parallel lines must be identical.
We have slope

, so the slope for the parallel line be the same.
Now, to find an equation that also passes through the given point, we use slope-point form,

, where our point

is substituted for

.

Now, we convert to slope-intercept form as such.

And we are done. :) We can verify graphically that these are indeed parallel lines. See attached.
Answer:
Given: Quadrilateral P QR S is a rectangle.
To prove :PR= Q S
Construction : Join PR and Q S.
Proof: In Rectangle PQRS, and
→ taking two triangles PSR and Δ QRS
1. PS = Q R
2. ∠ PS R = ∠ Q RS [Each being 90°]
3. S R is common.
→ ΔP SR ≅ Δ Q RS → [Side-Angle-Side Congruency]
∴ PR =Q S [ corresponding part of congruent triangles ]
Hence proved.
Answer:x equals 4
Step-by-step explanation:
Answer:did you check and see if anybody asked this question before??
Step-by-step explanation: